<span>The annual depreciation expense is $9,000, calculated as follows Cost of the asset is $80,000 less $8,000 salvage value which reduces the cost to $72,000. Useful life is 8 years. To determine annual depreciation expense using straight-line method, divide asset cost of $72,000 by 8 years of useful life equals $9,000 per year.</span>
5x+3y=9
2x-3y=5
5x+2x=9+5
7x=14
14/7x= 2
x=2
sub it in so you get y
5(2)+3y=9
10+3y=9 (-10 to get rid of it)
3y=-1
3y/-1= - 1/3
x= 2 y= - 1/3
Answer:
10 hours
Step-by-step explanation:
shara takes L
List of the first few prime numbers greater than 3:
5, 7, 11, 13, 17, 19, 23, 29
Now find the combination that you can multiply and still have a 2 digit number:
5 x 7 = 35
5 x 11 = 55
5 x 13 = 65
5 x 17 = 85
5 x 19 = 95
5 x 23 = 115 ( 3 digit number, can't use).
7 x 5 = 35
7 x 11 = 77
7 x 13 = 91
7 x 19 = 133 ( 3 digit number, can't use).
The largest 2 digit number would be 5 x 19 = 95
For the experiment, you need 2L of cola. Your first option would be to purchase 1 2L bottle of cola for $2.25.
To calculate the second option, let's convert milliliters to liters first. There are 1,000 milliliters in 1 liter. With this, we know that there are 2,000 milliliters in 2 liters. Option 2 comes in 500-milliliter cans, which means that you would need 4 of them (2,000/500 = 4). 4 cans multiplied by $0.50 would cost you $2.00.
Let's check the cost of your answer options.
A. 4 cans - As seen above, this would cost $2.00.
B. 1 bottle - From the question, we know this would cost $2.25.
C. 2 bottles - This would be more soda than you need and would cost $4.50 ($2.25x2)
D. 1 can - This would be .5L and not enough soda for the experiment.
E. 5 cans - This would cost $2.50, but would be an extra 500mL of soda.
F. 2 cans - This would only be 1L of soda and not enough for the experiment.
G. 3 cans - This would be 1.5L of soda and not enough for the experiment either.
For the best price option, you would choose A (four cans of soda). This would give you the amount of soda that you need at the lowest price.