Kinetic energy = (1/2) (mass) (speed squared)
Kinetic energy = (1/2) (400 kg) (17 m/s)²
Kinetic energy = (1/2) (400 kg) (289 m²/s²)
<em>Kinetic energy = 57,800 Joules</em>
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(That's some amazing house. I'd like to be there to see it.)
if the distance between the objects is doubled the force is reduced by a factor of 4
<h3>Whats is gravitational force?</h3>
Gravitational force is the force of attraction between objects in the universe.
f = G * m1 * m2 / r^2
f = gravitational force
G = gravitational constant
m1 = mass of object 1
m2 = mass of object 2
r = distance between the objects
From the formular, the gravitational force and the distance is an inverse relationship so increasing the distance by a factor results to reduction of the force by the square of the factor. hence doubling the distance which is distance mutiplied by 2 will lead to reduction of the force by 2^2 = 4
Therefore: The force decreases by a factor of 4.
hope it helps
I think it is B because it seems like the most valid choice.
The complete question is missing, so i have attached the complete question.
Answer:
A) FBD is attached.
B) The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
Explanation:
A) I've attached the image of the free body diagram.
B) The formula for the net force is given as;
F_net = mv²/r
We know that angular velocity;ω = v/r
Thus;
F_net = mω²r
Now, the minimum downward force is the weight and so;
mg = m(ω_min)²r
m will cancel out to give;
g = (ω_min)²r
(ω_min)² = g/r
ω_min = √(g/r)
The condition that must be satisfied is for ω_min = √(g/r)
C) The tension in the string would be zero. This is because at the smallest frequency, the only radially inward force at that point is the weight(force of gravity).
Answer: 15.66 °
Explanation: In order to solve this proble we have to consirer the Loretz force for charge partcles moving inside a magnetic field. Thsi force is given by:
F=q v×B = qvB sin α where α is teh angle between the velocity and magnetic field vectors.
From this expression and using the given values we obtain the following:
F/(q*v*B) = sin α
3.8 * 10^-13/(1.6*10^-19*8.9*10^6* 0.96)= 0.27
then α =15.66°
