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4 years ago

Balance the equation for magnasuin and oxygen to yield magnasuimoxide

Chemistry

1 answer:

Minchanka [31]4 years ago

6 0

Answer:

2Mg + O₂ → 2MgO

Explanation:

Chemical equation:

Mg + O₂ → MgO

Balanced chemical equation:

2Mg + O₂ → 2MgO

The balanced equation s given above and it completely follow the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction.

Steps to balanced the equation:

Step 1:

Mg + O₂ → MgO

Mg = 1 Mg = 1

O = 2 O = 1

Step 2:

2Mg + O₂ → MgO

Mg = 2 Mg = 1

O = 2 O = 1

Step 3:

2Mg + O₂ → 2MgO

Mg = 2 Mg = 2

O = 2 O = 2

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3 years ago

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What is the structural formula for 2-methyl 3-ethylbutane?

ivann1987 [24]

Answer:

Explanation:

2-methyl-3-ethylpentane | C8H18 | ChemSpider.

Boiling Point: 115.3±7.0 °C at 760 mmHg

Molecular Formula: C8H18

Density: 0.7±0.1 g/cm 3

Enthalpy of Vaporization: 32.9±0.0 kJ/mol

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3 years ago

The potential energy of an object increases 50 J. If there is no friction how much Kinect energy has been transformed

Mandarinka [93]

Answer:

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Explanation:

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3 years ago

ImTwo substances, A and B, initially at different temperatures, come into contact and reach thermal equilibrium. The mass of sub

kipiarov [429]

Answer:

Specific heat capacity of A is 1.05J/g°C

Explanation:

Hello,

In this question, we have to bodies in contact and there's transfer of energy (heat) between them. The heat loss in one body is equal to the heat gain in another body.

Heat loss in B = Heat gain in A

Data,

Mass of A = 6.44g

Initial temperature of A (T1) = 20.3°C

Mass of B = 25.1g

Initial temperature of B = 52.8°C

Final temperature after equilibrium is achieved (T3) = 46.7°C

Specific heat capacity of A (C1) = 1.17J/g°C

Specific heat capacity of B (C2) = ?

Heat loss in B = Heat gain in A

Q = mc∇T

Q = heat energy

M = mass of substance

C = specific heat capacity of the substance

∇T = change in temperature of the substance

M₂C₂(T₂ - T₃) = M₁C₁(T₃ - T₁)

Substitute the values into the variables and solve for C₁

25.1 × 1.17 × (52.8 - 46.7) = 6.44 × C₁ × (46.7 - 20.3)

179.1387 = 170.016C₁

Divide both sides by 170.016

C₁ = 179.1387 / 170.016

C₁ = 1.05J/g°C

The specific heat capacity of A is 1.05J/g°C

6 0

4 years ago

A solution is prepared by mixing equal volumes of 0.16 M HCl and 0.52 M HNO3. (Assume that volumes are additive.)

slega [8]

Answer:

The pH of the final solution is 0.16 .

Explanation:

The pH of the solution is defined as negative logarithm of hydrogen ion concentration in a solution.

$pH=-\log[H^+]$

Concentration of HCl = 0.16 M

$HCl(aq)\rightarrow H^+(aq)+Cl^-(aq)$

HCl is a string acid .1 molar of HCl gives 1 molar of of hydrogen ions.

$[H^+]=0.16 M$

Concentration of $HNO_3$ = 0.52 M

$HNO_3(aq)\rightarrow H^+(aq)+NO_{3}^-(aq)$

Nitric is a string acid .1 molar of nitric acid gives 1 molar of of hydrogen ions.

$[H^+]'=0.52 M$

Total hydrogen ion concentration:

$[H^+]''=[H^+]+[H^+]'$

=0.16 M+0.52 M=0.68 M

The pH of the solution:

$\pH=-\log[H^+]''=-\log[0.68 M]$

pH = 0.16

The pH of the final solution is 0.16 .

3 0

3 years ago