Answer:
B. Decreasing the pressure applied to the gas molecules
Explanation:
According to Boyle's Law, the pressure of the gas is inversely proportional to the volume of the gas. So, the option B is correctly implied to it.
Other values such as Temperature, Number of molecules are inversely proportional to the volume of the gas.
Size of the gas molecules is negligible as compared to volume.
Answer:
V₂ = 45.53 L
Explanation:
Given data:
Initial temperature = 850 K
Initial volume = 65 L
Initial pressure = 450 KPa
Final temperature = 430 K
Final pressure = 325 KPa
Final volume = ?
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 450 KPa× 65 L × 430 K / 850 K × 325KPa
V₂ = 12577500 KPa .L. K / 276250 K. KPa
V₂ = 45.53 L
Answer:
Explanation:
Group one:
The elements of group one shows +1 charge because these all are metals and lose their one valance electron.
Hydrogen lithium sodium potassium rubidium cesium francium
Group 2:
The elements of group two shows +2 charge because these all alkali metals and lose their two valance electrons.
beryllium magnesium calcium strontium barium radium
Group 3:
The elements of group three-B shoes +3 charge by losing three valance electrons.
Scandium yttrium lanthanum actinium
Group 4:
The elements of group 4th A and 4th B lose four electrons or gain four electrons to complete the octet and shows +4 or -4 charge.
Group 5:
Group 5th elements gain three electrons and shows -3 charge to complete the 8 electrons. (octet).
It involve the elements of group 5th A.
Group 6:
The elements of group 6A gain two electrons to complete the octet and shows -2 charge.
Group 7:
The elements of group 7A gain one electron to complete the octet and shows -1 charge.
Group 8:
The elements of group 8A are noble gases and have complete octet. That's why shows 0 charge.
Answer:
The percentage composition of a given compound is defined as <u>the ratio of the amount of each element to the total amount of individual elements present in the compound multiplied by 100. </u>Here, the quantity is measured in terms of grams of the elements present.
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