Answer:
D
Explanation:
1.) First convert to molar mass
18.1*1/231.533*18.01528=
<span>the ionization constant, Ka, for and indicator, HIn, is 1.0x10^-8. The color of the unionized form is red and the color of the ionized form is yellow. What is the color of the indicator in a solution whose pH is 4.6? (Hint: the color of an indicator can be estimated by considering the ratio of [HIn]/[In]. If the ratio is equal to or greater than 10, the color will bet hat of the unionized form. If the ratio is equal to or smaller than 0.1, the color will be that of the ionized form.
</span><span>Ka=[H+][A-]/[HA]
substitute for pH and find the value of A-/HA.
</span><span>
</span><span>so it'd just be 1x10^-8 divided by 4.6</span>
Answer: N = 2.78 × 10^23 atoms
There are N = 2.78 × 10^23 atoms in 70g of Au2cl6
Completed Question:
Calculate the number of gold atoms in a 70g sample of gold(III) chloride . Be sure your answer has a unit symbol if necessary, and round it to significant digits
Explanation:
Given:
Molar mass of Au2cl6 = 303.33g/mol
Mass of Au2cl6 = 70g
Number of moles of Au2cl6 = 70g/303.33g/mol = 0.231mol
According to the chemical formula of Au2cl6,
1 mole of Au2cl6 contains 2 moles of Au
Number of moles of Au = 2 × 0.231mol = 0.462mole
There are 6.022 × 10^23 atoms in 1 mole of an element.
Number of Atom of gold in 0.462 mole of gold is:
N = 0.462 mol × 6.022 × 10^23 atoms/mol
N = 2.78 × 10^23 atoms
Answer:
21.4666666667 g/cm^3
Explanation:
The density of a substance can be found by dividing the mass by the volume.
d=m/v
The mass of the sample is 16.1 grams and the volume is 0.75 cubic centimeters.
m= 16.1 g
v=0.75 cm^3
Substitute the values into the formula.
d=16.1 g / 0.75 cm^3
Divide
d= 21.4666666667 g/cm^3
The density of platinum is 21.4666666667 grams per cubic centimeter.