A scatter plot with a very strong linear association will have a correlation that is close to +/-1
Answer:
0.86
Step-by-step explanation:
Draw the triangle.
Since ∠J=90°, this is a right triangle, so we can use SOH-CAH-TOA to find sin∠I.
sin∠I = 56/65
sin∠I = 0.86
Answer:
A 2√2(cos 7π/4 + i sin 7π/4)
Step-by-step explanation:
A. 2√2(cos 7π/4 + i sin 7π/4)
2 sqrt(2) ( sqrt(2)/2 - sqrt(2)/2 i)
Distribute
2-2i
This is in the fourth quadrant
B. 2√2(cos 150° + i sin 150°)
2 sqrt(2) (-sqrt(3)/2 +1/2i)
-sqrt(6) +sqrt(2) i
This is in the third quadrant (NO)
C. 2(cos 7π/4 + i sin 7π/4)
2( ( sqrt(2)/2 - sqrt(2)/2 i))
sqrt(2) - sqrt(2) i
This is the fourth quadrant
D. 2(cos 90° + i sin 90°)
2(0+i)
2i
This is on the positive y axis NO
Now we need to decide between the two in the fourth quadrant.
The point has an x coordinate of 2 and a y coordinate of -2
This aligns with point A
Answer:
9
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
18-x=3
18-3=x
18-3=15
