Answer:
9.36
Explanation:
Sodium formate is the conjugate base of formic acid.
Also,
for sodium formate is 
Given that:
of formic acid = 
And, 
So,
Concentration = 0.35 M
HCOONa ⇒ Na⁺ + HCOO⁻
Consider the ICE take for the formate ion as:
HCOO⁻ + H₂O ⇄ HCOOH + OH⁻
At t=0 0.35 - -
At t =equilibrium (0.35-x) x x
The expression for dissociation constant of sodium formate is:
![K_{b}=\frac {[OH^-][HCOOH]}{[HCOO^-]}](https://tex.z-dn.net/?f=K_%7Bb%7D%3D%5Cfrac%20%7B%5BOH%5E-%5D%5BHCOOH%5D%7D%7B%5BHCOO%5E-%5D%7D)
Solving for x, we get:
x = 0.44×10⁻⁵ M
pOH = -log[OH⁻] = -log(0.44×10⁻⁵) = 4.64
pH + pOH = 14
So,
<u>pH = 14 - 4.64 = 9.36</u>
Answer:
66228
Molecular Formula: TiCl2 or Cl2Ti
Chemical Names: Titanium chloride (TiCl2) 10049-06-6 TiCl2 Titanium(II) chloride dichlorotitanium More...
Molecular Weight: 118.77 g/mol
Dates: Modify: 2019-08-10 Create: 2005-03-26
Explanation:
66228
Molecular Formula: TiCl2 or Cl2Ti
Chemical Names: Titanium chloride (TiCl2) 10049-06-6 TiCl2 Titanium(II) chloride dichlorotitanium More...
Molecular Weight: 118.77 g/mol
Dates: Modify: 2019-08-10 Create: 2005-03-26
Answer:milliliters to kilograms
Weight of 1000 milliliters (ml) of pure water at temperature 4 °C = 1 kilogram (kg).
Explanation:
hope this helps have a nice night ❤️❤️❤️
Answer:
18.9 moles
Explanation:
We have the following data:
V = 50 L
P = 12.4 atm
T= 127°C + 273 = 400 K
R = 0.082 L.atm/K.mol (it is the gas constant)
We use the ideal gas equation to calculate the number of moles n of the gas:
PV = nRT
⇒ n = PV/RT = (12.4 atm x 50 L)/(0.082 L.atm/K.mol x 400 K) = 18.9 mol
