Answer:
30 m/s
Step-by-step explanation:
Let's say the distance from the first car to the intersection is x, and the distance from the second car to the intersection is y.
The distance between the cars can be found with Pythagorean theorem:
d² = x² + y²
Taking derivative with respect to time:
2d dd/dt = 2x dx/dt + 2y dy/dt
d dd/dt = x dx/dt + y dy/dt
We know that x = 200, dx/dt = -25, y = 150, and dy/dt = -50/3.
To find dd/dt, we still need to find d.
d² = x² + y²
d² = (200)² + (150)²
d = 250
Plugging everything in:
250 dd/dt = (200) (-25) + (150) (-50/3)
dd/dt = -30
The cars are approaching each other at a rate of 30 m/s at that instant.
Answer:
24.23
Step-by-step explanation:
The tan(x) would equal to the opposite side over the adjacent one
So 9/20. To get the degree we need to get the arctan of it, so arctan(9/20) = 24.23
Answer:
A. The solutions are 
.
B. The factored form of the quadratic expression 
Step-by-step explanation:
A. To find the solutions to the quadratic equation 
you must:
The solutions are:
B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.
To factor 
:
First, multiply the constant in the polynomial by 
where is equal to -1.
Since both terms are perfect squares, factor using the difference of squares formula
