Answer:
42
Step-by-step explanation:
With a simple problem like this you can just do 84/2.
Answer:
0.6045 = 60.45% probability that, in any seven-day week, the computer will crash more than 3 times.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given time interval.
The computer that controls a bank's automatic teller machine crashes a mean of 0.6 per day.
7 day week, so 
What is the probability that, in any seven-day week, the computer will crash more than 3 times?
Either it crashes 3 or less times, or it crashes more than 3 times. The sum of the probabilities of these events is decimal 1. So

We want P(X > 3). So

In which








0.6045 = 60.45% probability that, in any seven-day week, the computer will crash more than 3 times.
X = necklaces, y = bracelets
at least twice as many bracelets as necklaces
y > = 2x <===
x > 0 <===
half hour for necklace, 1 hr for bracelet...fewer then 20 hrs
0.5x + y < 20 <==
Answer:
The answer to your question is:
Step-by-step explanation:
12.-
x² - 6x = 5
x² - 6x + (3)² = 5 + (3)²
x² - 6x + 9 = 5 + 9
(x - 3)² = 14
13.- x² - 6x = 12
x² - 6x + (3)² = 12 + (3)²
x² - 6x + 9 = 12 + 9
(x - 3)² = 21
x - 3 = ±√21
x1 = √21 + 3 x2 = -√21 + 3
x1 = 7.58 x2 = -1.58
14.- 2x² - 24x = - 20 Divide by 2
x² - 12 x = -10
x² - 12x + (6)² = - 10 + (6)²
x² - 12x + 36 = - 10 + 36
( x - 6) ² = 26
x - 6 = ±√26
x1 = √26 + 6 x2 = -√26 + 6
x1 = 11.1 x2 = 0.9