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nlexa [21]
3 years ago
6

Why is the structure of atom important to scientist?

Chemistry
2 answers:
Kruka [31]3 years ago
8 0
The structure of an atom is important to scientist because an atom usallay makes up everything around you even u are made of atoms they are the tinest thing that we have found yet to belive in kk.

Hope this helps!
Olenka [21]3 years ago
7 0
Because they form the basic building blocks of all visible matter in the universe. 
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Heat energy is released to warm the house
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Please help me and dont send me a bitly link its a scam
melamori03 [73]

Answer:

Explanation:

4)6.27x10^20/(6.02x10^23)(u should have this number on your formula sheet)=0.001 mol

5)7.4x6.02x10^23=44.548x10^23atoms

6)molar mass for K is 39.10g/mol

3.27x39.10=127.86g

Im bad at sig figs. Just do it urself(:p

6 0
4 years ago
Recall rem = rad x q radiation weighting factor (q): the ability to transfer energy to the body 1 for photons 1 for electrons 2
tino4ka555 [31]

The biological risk for the first person than the second as a result of radiation weighting is 10 times.

<h3>What is radiation weighting factor?</h3>

As stated in the question, radiation weighting factor (q) is the ability to transfer energy to the body.

If radiation factor of proton = 2, and radiation factor of alpha particles = 20.

  • First person is exposed to alpha radiation = 20
  • Second person is exposed to protons = 2

Risk of first person with respect to second person = 20/2 = 10 times higher

Learn more about radiation factor here: brainly.com/question/24039736

#SPJ4

6 0
2 years ago
How do I solve this?
ira [324]
Sorry, I can't really see the question )-:
6 0
4 years ago
What is the volume of 12.0 grams of oxygen gas at STP<br><br> Atomic mass:O = 15.99 grams/moles
strojnjashka [21]

Answer:

16.82 L.

Explanation:

  • We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm (P = 1.0 atm, STP conditions).

V is the volume of the gas in L (V = ??? L).

n is the no. of moles of the gas in mol (n = mass/molar mass = (12.0 g)/(15.99 g/mol) = 0.7505 mol).

R is the general gas constant (R = 0.0821 L.atm/mol.K),

T is the temperature of the gas in K (T = 0.0°C + 273 = 273.0 K, STP conditions).

<em>∴ V = nRT/P</em> = (0.7505 mol)(0.0821 L.atm/mol.K)(273.0 K)/(1.0 atm) = <em>16.82 L.</em>

6 0
4 years ago
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