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Sever21 [200]
3 years ago
7

Diagram the cross section of a graduated cylinder, illustrating how to read the meniscus.

Physics
2 answers:
denis-greek [22]3 years ago
7 0

Answer:

Explanation:

While taking the reading from a test tube( or cross section of a graduated cylinder) we note the value at lower meniscus. We should also keep in mind at the time of reading, our hand should be stable(to minimize human error) and at this stable condition lower meniscus would the the right reading.

Gre4nikov [31]3 years ago
3 0
<span>When taking the reading you must see where the lower meniscus lies . The value at which the lower meniscus lies is your reading .</span>
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A box is sliding down a ramp how many force vectors does the box have
vlada-n [284]
Well you’d have a force due to gravity, the normal force which will be perpendicular to the sources (meaning you’ll have components to this vector), and you’d have the force of friction opposing the motion of the box. I’m also assuming there’s no air resistance. In this case you’d have three vector forces.
6 0
3 years ago
How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is 3.33××10âˆ
AlekseyPX

Answer:

There are 756.25 electrons present on each sphere.

Explanation:

Given that,

The force of repression between electrons, F=3.33\times 10^{-21}\ N

Let the distance between charges, d = 0.2 m

The electric force of repulsion between the electrons is given by :

F=k\dfrac{q^2}{r^2}

q=\sqrt{\dfrac{Fr^2}{k}}

q=\sqrt{\dfrac{3.33\times 10^{-21}\times (0.2)^2}{9\times 10^9}}

q=1.21\times 10^{-16}\ C

Let n are the number of excess electrons present on each sphere. It can be calculated using quantization of charges. It is given by :

q = ne

n=\dfrac{q}{e}

n=\dfrac{1.21\times 10^{-16}}{1.6\times 10^{-19}}

n = 756.25 electrons

So, there are 756.25 electrons present on each sphere. Hence, this is the required solution.

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4 years ago
What is the Nearest Galaxy from the Milky Way
Vsevolod [243]

Answer:

the andromeda galaxy

Explanation:

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6 0
3 years ago
Read 2 more answers
How much voltage is required to run 0.42 A of current through a 150
igomit [66]

The voltage in the resistor is 63 V

Explanation:

We can solve the problem by applying Ohm's law, which states the relationship between voltage, current and resistance in a resistor:

V=RI

where

V is the voltage

R is the resistance

I is the current

For the resistor in this problem, we have:

I = 0.42 A is the current

R=150 \Omega is the resistance

Substituting into the equation, we find the voltage needed:

V=(0.42)(150)=63 V

Learn more about voltage and current:

brainly.com/question/4438943

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4 0
3 years ago
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Aleksandr-060686 [28]

Answer:

b -algae

Explanation:

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