Answer:
C
Explanation:
n= 7.7mol
P= 9120pa
T = 329.15K
PV=nRT
V= nRT/P
V= (7.7×8.314×329.15)/9120
V= 2.308meter cubic
V= 2308L
Answer:
a combination of two or more elements called a compound
43.62m
Explanation:
Given parameters:
Energy = 8550J
Mass of bell = 20kg
Unknown:
Height of the bell = ?
Solution:
As this state, the bell possesses potential energy. Potential energy is the energy at rest in a body. It is due to the position of the body.
Potential energy = m g h
m is the mass of the body
g is the acceleration due to gravity of the body
h is the height of the body
The unknown is h and we should solve for it.
g = 9.8m/s²
Input the variables;
8550 = 20 x 9.8 x h
h = 43.62m
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Potential energy brainly.com/question/10770261
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It absorbed 41,600 joules.
Explanation:
If the sample of sucrose burnt in the calorimeter releases 41600Joules of heat, then the water in the calorimeter will absorb 41600J.
The heat lost by burning the sucrose in the calorimeter is also the heat gained by the water therein.
A calorimeter is a device by prevents heat loss to the environment in any form.
It is specially designed to minimize heat loss by conduction, convection radiation.
Therefore, since no heat is lost, the heat released by burning the sucrose is used in heating the water there.
learn more:
Specific heat brainly.com/question/7210400
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<u>Answer:</u> The mass percent of lead in lead (IV) carbonate is 63.32 %
<u>Explanation:</u>
The given chemical formula of lead (IV) carbonate is 
To calculate the mass percentage of lead in lead (IV) carbonate, we use the equation:
Mass of lead = (1 × 207.2) = 207.2 g
Mass of lead (IV) carbonate = [(1 × 207.2) + (2 × 12) + (6 × 16)] = 327.2 g
Putting values in above equation, we get:
Hence, the mass percent of lead in lead (IV) carbonate is 63.32 %
