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White raven [17]
3 years ago
11

Your friend wants to be magician and intends to use Earth’s magnetic field to suspend a current-carrying wire above the stage. H

e asks you to estimate the minimum current needed to suspend the wire just above Earth’s surface at the equator (where Earth’s magnetic field is horizontal). Assume the wire has a mass of 10 g, and length of 1.0 m. Would you advise him to proceed with his plans for this act?
Physics
1 answer:
sesenic [268]3 years ago
7 0

Answer:

I=1960A

Explanation:

Under this  condition, . In order to suspend the wire, this magnetic force would  have to be equal in magnitude to the gravitational force exerted by Earth on the  wire the maximum force at angle

F=ILxB

Now to the suspend the wire so use the maximum force and solve to the current knowing the magnetic field of the earth

∑Fy=0

F_{m}-F_{g}=0

I*L*\beta-m*g=0

Solve to I current

I=\frac{m*g}{L*\beta}

I=\frac{10x10^{-3}kg*9.8m/s^2}{1m*0.5x10{-4}T}

I=1960A

I suggest do an toher act is really risk that current for an act

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What do you mean by average velocity​
mina [271]

Answer:

Here is the answer. Hope this helps you!

Explanation:

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u + v/2 = v_{av}

Average velocity = Average speed

during motion in a straight line. therefore, the above mentioned formula can be used for calculating average speed as well, when the direction is one and only the same, that is, during motion in a straight line. The S.I unit remains the same-

m/s.

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7 0
3 years ago
Covalent bonds form because most atoms seek to have how many electrons in their most outer shell?
suter [353]

Answer: 8

Explanation:

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4 0
4 years ago
16. A 95kg fullback, running at 8.2m/s, collided in midair with a 128 kg defensive tackle moving in the opposite direction. Both
Daniel [21]

a) 779 kg m/s

The momentum of an object is given by:

p = mv

where

m is the mass of the object

v is its velocity

For the fullback before the collision,

m = 95 kg

v = 8.2 m/s

Therefore, his momentum was:

p=mv=(95)(8.2)=779 kg m/s

b) -779 kg m/s

After the collision, both the fullback and the tackle come to a stop: this means that their momentum after the collision is zero,

p' = 0

The initial momentum of the fullback was

p = 779 kg m/s

Therefore, his change in momentum is

\Delta p = p' -p =0-779  = -779 kg m/s

where the negative sign indicates that the direction is opposite to the initial direction of motion.

c) -779 kg m/s

Here we can apply the law of conservation of momentum. In fact, the total momentum before and after the collision must be conserved. So we can write:

p_f + p_t = p'

where

p_f is the initial momentum of the fullback

p_t is the initial momentum of the tackle

p' is the final combined momentum after the collision

We already know that

p_f = 779 kg m/s\\p' = 0

Therefore, we can find the tackle's original momentum:

p_t = p'-p_f = 0-(779) = -779 kg m/s

where the negative sign indicates that the direction is opposite to the initial direction of motion of the fullback.

e) -6.1 m/s

To find the velocity of the tackle, we can use again the equation of the momentum:

p = mv

where here we have

p=-779 kg m/s is the original momentum of the tackle

m = 128 kg is his mass

Solving the equation for v, we find the tackle's original velocity:

v=\frac{p}{m}=\frac{-779}{128}=-6.1 m/s

So, he was moving at 6.1 m/s in the direction opposite to the fullback.

4 0
3 years ago
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