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saw5 [17]
3 years ago
9

In an experiment , which variable do you change

Physics
1 answer:
Tomtit [17]3 years ago
7 0
The independent variable
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The cluster of decisions that managers make to assist the organization to achieve its goals is known as:
vfiekz [6]
The correct answer is letter C. SWOT analysis. The cluster of decisions that managers make to assist the organization to achieve its goals is known as SWOT Analysis.
Here are the choices.A. Strategy B. Scenario planning C. SWOT analysis D. Diversification E. Related diversification
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2 years ago
A battery supplies 0.75 A to three resistors connected in parallel. The current through the first resistor is 0.24 A and the cur
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Total current flow in circuit=0.75
Current flow through third resistor=0.75-(0.24+0.22)
=0.29
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3 years ago
What cloud makes hail
MArishka [77]

Answer:

Cumulonimbus

Hail development. Hail is a type of strong precipitation, which is shaped in rainstorms mists (Cumulonimbus). Tempests mists comprises of beads of fluid water (at temperatures lower than 0°с, the beads can be in a thermodynamically instable supercooled condition) and ice gems

Explanation:

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2 years ago
Which of the following is an abiotic limiting factor for a plant population in an ecosystem?
Ludmilka [50]

Correct answer is Availability of soil minerals.

There are two types of limiting factors that affect plant population in a ecosystem. They are:

  1. Biotic
  2. Abiotic

Biotic factors includes food, diseases etc. Such as Invasive weed species, seed dispersal by wind, disease-causing fungal spores are examples of biotic limiting factor.

Abiotic factors include sunlight, temperature and chemical environment. The availability of soil mineral is an example of abiotic limiting factor. Growth of plant population depends on availability of soil minerals.

8 0
2 years ago
A house that was heated by electric resistance heaters consumed 1200 kWh of electric energy in a winter month. If this house wer
Marysya12 [62]

Answer:

$84

Explanation:

The coefficient of performance (COP) show the relationship between the power (kW) output of the heat pump and the power (kW) input to the compressor.

The heater consumed by the heater is 1200 kWh.

For a heat pump with a COP of 2.4, the electric input needed to produce an output of 1200 kWh is:

Electric input to heat pump = 1200 / 2.4 = 500 kWh

That means that supplying a heat pump with 500 kWh produces an output of 1200 kWh

The amount of power saved = power consumed by heater - power consumed by heat pump = 1200 - 500 = 700 kWh

Money saved = $0.12/kWh * 700 kWh = $84

6 0
2 years ago
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