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jasenka [17]
3 years ago
10

The gravitational force between two objects:

Physics
2 answers:
LUCKY_DIMON [66]3 years ago
8 0

The gravitational force between two objects INcreases

if either object gains mass , and also increases if the objects

are moved closer together.


Unlike the electrostatic force between charges, the gravitational

force between masses ALWAYS pulls them together, and never

pushes them apart.

jasenka [17]3 years ago
7 0

C. Gravitational force between two objects of masses m1/m2

is defined by Gm1xm2/r^2, where G is a universal constant, and r is the distance between the masses. This shows you why B is wrong; it would increase. Also, A is not a good choice, as shown. In the case of B, it would increase by say, 2/1 to 4/1 by doubling ones mass. In C's case the bottom would decrease on the fraction alot (square) if they were moved closer, thus the force would be greater.

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Correct question:

Consider the motion of a 4.00-kg particle that moves with potential energy given by

U(x) = \frac{(2.0 Jm)}{x}+ \frac{(4.0 Jm^2)}{x^2}

a) Suppose the particle is moving with a speed of 3.00 m/s when it is located at x = 1.00 m. What is the speed of the object when it is located at x = 5.00 m?

b) What is the magnitude of the force on the 4.00-kg particle when it is located at x = 5.00 m?

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b) 0.016 N

Explanation:

a) given:

V = 3.00 m/s

x1 = 1.00 m

x = 5.00

u(x) = \frac{-2}{x} + \frac{4}{x^2}

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u(5) = \frac{-2}{5} + \frac{4}{5^2}

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Using conservation of energy,

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Vf² = (22+0.24) / 2

Vf = \sqrt{frac{22.4}{2}

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\frac{-du(x)}{dx} = \frac{-d}{dx} [\frac{-2}{x}+ \frac{4}{x^2}

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At x = 5.0 m

\frac{2}{5^2} - \frac{8}{5^3}

F = \frac{2}{25} - \frac{8}{125}

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