Answer:
Explanation:
Given
Initial velocity u = 200m/s
Final velocity = 4m/s
Distance S = 4000m
Required
Acceleration
Substitute the given parameters into the formula
v² = u²+2as
4² = 200²+2a(4000)
16 = 40000+8000a
8000a = 16-40000
8000a = -39,984
a = - 39,984/8000
a = -4.998m/s²
Hence the acceleration is -4.998m/s²
Answer:
1.7333333m/s²
Explanation:
Tension of the line = the weight + force from pulling up the fish
30N = mg + ma
30 = (6)(9.8) + (6)a
10.4 = 6a
∴ a = 1.7333333m/s²
The frequency of this wave is 3
<h2>Answer:</h2>
<u>Distance covered is 6.9 meters</u>
<h2>Explanation:</h2>
Data given:
Work Done = 345 kJ = 345000 J
Force = 5 x 10 ^ 4 = 50000 N
Distance = ?
Solution:
As we know that
Work Done = Force applied x Distance covered
By arranging the equation we get
Work / Force = Distance covered
By putting the values
345000 / 50000 = 6.9
So distance covered is 6.9 meters
Answer:
The same pendulum could be adjusted to have the same period, in the equator must have a length of 3.949m.
Explanation:
Tnp= 4 sec
gnp= 9.83 m/sec²
Lnp= 3.97m
Tequ= 4 sec
gequ= 9.78 m/sec²
Lequ=?
Lequ= (Lnp* gequ) / gnp
Lequ= 3.949 m