What is the outcome of the experoment?

The map shows the distribution of three species of organisms observed during a population survey. Identify the pattern of distri

Pepsi [2]

Answer:

I DONOT NOW SOORY

Explanation:

3 0

3 years ago

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Equal volumes of H2 and O2 are placed in a balloon and then ignited. Assuming that the reaction goes to completion, which gas wi

Sonbull [250]

Answer: Oxygen

Explanation:

$2H_2+O_2\rightarrow 2H_2O$

As seen from the balanced equation:

2 moles of hydrogen combine with 1 mole of oxygen or 1 mole of hydrogen combine with 1/2 mole of oxygen.

According to Avogadro's law, equal volumes of gases contain equal number of molecules and hence equal number of moles.

Thus if x moles of both gases are present, x moles of hydrogen will combine with $\frac{x}{2}$ moles of oxygen and $x-\frac{x}{2}=\frac{x}{2}$ moles of oxygen will be left used and will be in excess.

7 0

3 years ago

The emission of a Beta particle has the effect of...? A. Decreasing mass by one unit /B.Increasing mass by one unit / C. - No ch

vodomira [7]

The emission of a beta particle has the effect of : C. No change in mass

basically, beta particle has a very very little mass compared to the proton and neutrons, so little to the point that it never considered as a change in mass. But it does decreases the charge of atom

hope this helps

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3 years ago

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Why do South Pole and North Pole and South Pole attract?

vfiekz [6]

They have a magnetic attraction.

6 0

3 years ago

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Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A soluti

ella [17]

Answer :

The mass of excess mass of $Na_2CO_3$ , $AgNO_3,Ag_2CO_3\text{ and }NaNO_3$ are, 1.908 g, 0 g, 12.144 g and 3.74 g respectively.

Explanation : Given,

Mass of $Na_2CO_3$ = 4.25 g

Mass of $AgNO_3$ = 7.50 g

Molar mass of $Na_2CO_3$ = 106 g/mole

Molar mass of $AgNO_3$ = 170 g/mole

Molar mass of $Ag_2CO_3$ = 276 g/mole

Molar mass of $NaNO_3$ = 85 g/mole

First we have to calculate the moles of $Na_2CO_3$ and $AgNO_3$ .

$\text{Moles of }Na_2CO_3=\frac{\text{Mass of }Na_2CO_3}{\text{Molar mass of }Na_2CO_3}=\frac{4.25g}{106g/mole}=0.040moles$

$\text{Moles of }AgNO_3=\frac{\text{Mass of }AgNO_3}{\text{Molar mass of }AgNO_3}=\frac{7.50g}{170g/mole}=0.044moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

$Na_2CO_3+2AgNO_3\rightarrow Ag_2CO_3+2NaNO_3$

From the balanced reaction we conclude that

As, 2 moles of $AgNO_3$ react with 1 mole of $Na_2CO_3$

So, 0.044 moles of $AgNO_3$ react with $\frac{0.044}{2}=0.022$ moles of $Na_2CO_3$

From this we conclude that, $Na_2CO_3$ is an excess reagent because the given moles are greater than the required moles and $AgNO_3$ is a limiting reagent and it limits the formation of product.

The excess mole of $Na_2CO_3$ = 0.040 - 0.022 = 0.018 mole

Now we have to calculate the mass of excess mole of $Na_2CO_3$ .

$\text{Mass of }Na_2CO_3=\text{Moles of }Na_2CO_3\times \text{Molar mass of }Na_2CO_3=(0.018mole)\times (106g/mole)=1.908g$