Explanation:
Atomic number of magnesium is 12 and its electronic distribution is 2, 8, 2. To attain noble gas configuration it is necessary for the magnesium atom to lose two valence electrons and therefore, it forms
ions.
On the other hand, atomic number of oxygen atom is 8 and its electronic distribution is 2, 6. To attain noble gas configuration it needs to gain two electrons. And, on gaining the electrons it forms
ions.
Hence, when both magnesium and oxygen ions chemically combine with each other then it forms the compound magnesium oxide (
).
This is because magnesium transfer its two valence electrons to the oxygen atom and due to the formation of opposite charges on these atoms they get attracted towards each other.
Answer:
Insoluble in water:
Explanation:
Water turns out to be a good solvent for ionic substances, or in general, polarized covalent substances. On the other hand, it is not a good solvent for non-polar substances, these being the vast majority of covalent substances.
Answer:
These reactions are similar because the process is similar and the products are carbon dioxide they are different because the substances are different to outgo these reactions
Explanation:
Sodium is the reducing agent because a reducing agent is always the donor of electrons.
Answer:
- 602 mg of CO₂ and 94.8 mg of H₂O
Explanation:
The<em> yield</em> is measured by the amount of each product produced by the reaction.
The chemical formula of <em>fluorene</em> is C₁₃H₁₀, and its molar mass is 166.223 g/mol.
The <em>oxidation</em>, also know as combustion, of this hydrocarbon is represented by the following balanced chemical equation:
![2C_{13}H_{10}+31O_2\rightarrow 26CO_2+10H_2O](https://tex.z-dn.net/?f=2C_%7B13%7DH_%7B10%7D%2B31O_2%5Crightarrow%2026CO_2%2B10H_2O)
To calculate the yield follow these steps:
<u>1. Mole ratio</u>
![2molC_{13}H_{10}:31molO_2:26molCO_2:10molH_2O](https://tex.z-dn.net/?f=2molC_%7B13%7DH_%7B10%7D%3A31molO_2%3A26molCO_2%3A10molH_2O)
<u />
<u>2. Convert 175mg of fluorene to number of moles</u>
- Number of moles = mass in grams / molar mass
<u>3. Set a proportion for each product of the reaction</u>
a) <u>For CO₂</u>
i) number of moles
![2molC_{10}H_{13}/26molCO_2=0.0010528molC_{10}H{13}/x](https://tex.z-dn.net/?f=2molC_%7B10%7DH_%7B13%7D%2F26molCO_2%3D0.0010528molC_%7B10%7DH%7B13%7D%2Fx)
![x=0.0010528molC_{10}H_{13}\times 26molCO_2/2molC_{10}H_{13}=0.013686molCO_2](https://tex.z-dn.net/?f=x%3D0.0010528molC_%7B10%7DH_%7B13%7D%5Ctimes%2026molCO_2%2F2molC_%7B10%7DH_%7B13%7D%3D0.013686molCO_2)
ii) mass in grams
The molar mass of CO₂ is 44.01g/mol
- mass = number of moles × molar mass
- mass = 0.013686 moles × 44.01 g/mol = 0.602 g = 602mg
b) <u>For H₂O</u>
i) number of moles
![0.0010528molC_{10}H_{13}\times10molH_2O/2molC_{10}H_{13}=0.00526molH_2O](https://tex.z-dn.net/?f=0.0010528molC_%7B10%7DH_%7B13%7D%5Ctimes10molH_2O%2F2molC_%7B10%7DH_%7B13%7D%3D0.00526molH_2O)
ii) mass in grams
The molar mass of H₂O is 18.015g/mol
- mass = number of moles × molar mass
- mass = 0.00526 moles × 18.015 g/mol = 0.0948mg = 94.8 mg