What is the work required for the separation of air (21-mol-% oxygen and 79-mol-% nitrogen) at 25°C and 1 bar in a steady-flow p
1 answer:
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621.4L
Explanation:
Given parameters:
Initial volume = 547L
Initial temperature = 331K
Final temperature = 376K
Unknown:
Final volume = ?
Solution:
The appropriate gas law to use is the Charles's law.
The Charles's law shows the relationship between the volume and temperature of a gas under constant pressure.
The law states that "The volume of a fixed of a gas varies directly as its absolute temperature if the pressure is constant".
Mathematically;
V₁ is the initial volume
T₁ is the initial temperature
V₂ is the final volume
T₂ is the final temperature
Since the unknown is the final volume, we make it the subject of the expression;
V₂ =
V₂ = 621.4L
learn more:
Boyle's law brainly.com/question/8928288
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