Answer:
The probability that sample mean differ the true greater than 2.1 will be 2.8070 %
Step-by-step explanation:
Given:
Sample mean =46 dollars
standard deviation=8
n=53
To Find :
Probability that sample mean would differ from true mean by greater than 2.1
Solution;
<em>This sample distribution mean problem,</em>
so for that
calculate Z- value
Z=(sample mean - true mean)/(standard deviation/Sqrt(n))
Z=-2.1/(8/Sqrt(53))
Z=-2.1*Sqrt(53)/8
Z=-1.91102
Now for P(X≥2.1)=P(Z≥-1.91102)
Using Z-table,
For Z=-1.91
P(X>2.1)=0.02807
Answer:
x=6 , y=17
Step-by-step explanation
3x-1=2x+5
+1 -2x
x=6
plug in 6 for x to solve y
Answer:
h(x)=x²+6 and g(x)=8x-5
prove that hg(x)=19
Step-by-step explanation:
step 1: hog(x)=h[g(x)]
step 2: h(8x-5)
step 3: h(8x-5)= (8x-5)²+6
step 4: (8x-5)(8x-5)+6
step 5: 16x² +15x +6
A
(X-7)(x-4) -> x^2 -11x + 28
Multiply that by the 2 and you get the original equation!
