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-BARSIC- [3]
3 years ago
14

You are provided with a beaker, wire, two nails, battery, bulb and dilute soultions of HCl, HNO3, alcohol and glucose. How will

you identify the acids from the given solutions using the given materials?
Chemistry
1 answer:
trasher [3.6K]3 years ago
5 0

Answer:

Acid solutions will be those which lights up a bulb when a circuit is connected through them.

Explanation:

Acid solutions such as HCl and HNO3 are polar in nature and permits the flow of electricity through them. Whereas non-polar solutions like ethanol and glucose solution will not allow the flow of electricity through them.

Therefore, when an electric circuit is completed by dipping the nails connected to a battery and a bulb into the different solutions, the lighting up of the bulb indicates which solutions are acids.

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A photon has 8.0 × 10–15 J of energy. Planck’s constant is 6.63 × 10–34 J•s.
NISA [10]
The frequency of a photon with an energy of 8.0 × 10⁻¹⁵ J is  1.21 × 10¹⁹  /s.

How to arrived at the answer is attached below

Please note that v= frequency; h= Plank's constant; E= Energy

7 0
3 years ago
Question 25 a chemist determined by measurements that 0.020 moles of mercury participated in a chemical reaction. calculate the
sammy [17]
To solve this question, we first need to know the mass of one mole of mercury. This can be done by checking the periodic table.

From the periodic table, we can see that:
molar mass of mercury = 200.59 grams/mole.

From the measurements, the chemist found that the participated amount of mercury is 0.02 moles.

We can simply determine the mass of 0.02 moles by doing cross multiplication as follows:
mass of 0.02 moles = (0.02 x 200.59) / 1 = 4.0118 grams

Rounding the answer to 2 significant digits, we get:
mass of 0.02 moles = 4.01 grams
4 0
4 years ago
While watching tv in your room one nigh, you decide to have some Oreos and a glass of milk. there were only 3 Oreos and science
sveta [45]

Answer:

yes it did.

Explanation:

the product must have produced a smell therefore it created a gas. this means it was a chemical reaction

8 0
3 years ago
The titration of Na2CO3 with HCl has the following qualitative profile: a. Identify the major species in solution at points A-F.
exis [7]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

Note: This question is incomplete and lacks very important data to solve this question. But I have found the similar question which shows the profiles about which question discusses. Using the data from that question, I have solved the question.

a) We need to find the major species from A to F.

Major Species at A:

1. Na_{2} CO_{3}

Major Species at B:

1. Na_{2} CO_{3}

2. NaHCO_{3}

Major Species at C:

1. NaHCO_{3}

Major Species at D:

1. NaHCO_{3}

2. H_{2}CO_{3}

Major Species at E:

1. H_{2}CO_{3}

Major Species at F:

1. H_{2}CO_{3}

b) pH calculation:

At Halfway point B:

pH = pKa_{1} + log[CO_{3}.^{-2}]/[HCO_{3}.^{-1}]

pH = pKa_{1} = 6.35

Similarly, at halfway point D.  

At point D,

pH = pKa_{2} + log [HCO_{3}.^{-1}]/[H2CO_{3}]

pH = pKa_{2} = 10.33

8 0
3 years ago
What is the density of a object whose dimensions are 5.54
Tcecarenko [31]

The object with dimensions 5.54\ cm \times 10.6\ cm \times 199\ cm and with mass 250.6 g will have a density equal to 0.02144\ g/cm^3.

<h3><u>Explanation:</u></h3>

<u>Given:</u>

Dimensions of the object = 5.54\ cm \times 10.6\ cm \times 199\ cm

length = l = 5.54 cm

width = w = 10.6 cm

height = h = 199 cm

Mass of the object = m = 250.6 g

<u>Formula:</u>

The relation between density, mass and volume of any object is given by:

Density = \frac{ Mass }{Volume}

Since volume of an object with length (l), width (w) and height (h) [assuming a rectangular object] can be defined as,

V = l \times w \times h =5.54 \times 10.6 \times 199

Volume = V = 11686.076\ cm^3

Density = Mass / Volume = \frac{250}{11686.076}

Density = 0.02144 g/cm^3

Density of the object is 0.02144 g/cm^3

5 0
3 years ago
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