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2 years ago

I have no idea what this is about, I keep reading it over and other again, but I still don't understand! Help?

Chemistry

1 answer:

erastova [34]2 years ago

6 0

Answer:

yeah i don't get it please do not mark brainleast please

Explanation:

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Misha Larkins [42]

C. polymerization....

4 0

3 years ago

how many moles of nitrogen gas are produced in the reaction if we started with 6 moles of ammonium nitrate

babunello [35]

9moIN2 :
The molar ratio between Nitrogen and ammonia is
1
:
3
, therefore, to produce 18 moles of ammonia, we will need

7 0

3 years ago

When heated, magnesium combines readily with excess oxygen in the air to produce magnesium oxide, as shown in the following unba

aev [14]

<u>Answer:</u> The given chemical reaction can be classified as synthesis and exothermic.

<u>Explanation:</u>

A synthesis reaction is defined as the reaction where two small chemical species combine in their elemental state to form a single large chemical species.

Exothermic reactions are defined as the reactions in which heat is released by the reaction. The heat is written on the product side of the reaction.

For the given chemical reaction:

$Mg(s)+O_2(g)\rightarrow MgO(s)+\text{heat}$

The above chemical reaction is a type of synthesis and exothermic as two substances in their elemental state are combining. Also, heat is getting released in the reaction.

Hence, the given chemical reaction can be classified as synthesis and exothermic.

4 0

2 years ago

3. Burns from boiling water can be severe, caused by the transfer of energy from the boiling water to the

Free_Kalibri [48]

Answer:

Q = 3937.56 J

Explanation:

Heat transferred due to change in temperature is given by :

$Q=mc\Delta T$

c is the specific heat of water, c=4.18 J/g-°C

We have, m = 15 g, $T_i=100^{\circ} C\ \text{and}\ T_f=37.2^{\circ} C$

So,

$Q=15\times 4.18\times (37.2-100)\\Q=-3937.56\ J$

Hence, 3937.56 J of heat is transferred.

8 0

3 years ago

The standard enthalpy of formation (ΔHf°) of calcium carbonate is –1207 kJ/mol. Which ONE of the equations below has ΔH° = –1207

Art [367]

Answer:

A) Ca(s) + C(s) + 3/2 O₂(g) → CaCO₃(s)

Explanation:

Standard enthalpy of formation of a chemical is defined as the change in enthalpy durin the formation of 1 mole of the substance from its constituent elements in their standard states.

The consituent elements of calcium carbonate, CaCO₃, in their standard states (States you will find this pure elements in nature), are:

Ca(s), C(s) and O₂(g)

That means, the equation that represents standard enthalpy of CaCO₃ is:

<em>Is the equation that has ΔH° = -1207kJ/mol</em>

3 0

3 years ago