Answer:
a) 3.969
b) 3.489
Explanation:
a) Calculate the pk, value of the acid HA
PH of salt hydrolysis
P
= 1/2 ( pkw + pka + logC )
8.7 * 2 = 14 + log ( 0.27 ) + Pka
∴ Pka = 3.9686 ≈ 3.969
b) Calculate the PH of a solution containing 0.3 M HA and 0.1 M NaA
PH = Pka + log ( salt / acid )
= 3.9686 + log ( 0.1 / 0.3 )
= 3.9686 - 0.48 = 3.489
Answer: The percent ionization of 
in a 0.050 M 
solution is 8.9 %
Explanation:
cM 0 0
So dissociation constant will be:
Give c= concentration = 0.050 M and 
= degree of ionisation = ?
Putting in the values we get:
percent ionisation =
Answer:
Explanation:
A substance with a high specific heat, such as the water in Figure 9, heats up and cools down slowly because a much larger quantity of heat is required to cause its temperature to rise or fall by the same amount. Matter can change from one state to another when thermal energy is absorbed or released.
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