Explanation:
Copper sulphate reacts with potassium iodide to form cuprous iodide and iodine.
2CuSO
4
+4KI→Cu
2
I
2
↓+I
2
+2K
2
SO
4
Thus, CuI
2
is not formed in this reaction.
Hence, the option B is incorrect and option A is correct.
The liberated iodine is titrated with sodium thiosulphate to form sodium tetrathionate.
2Na
2
S
2
O
3
+I
2
→Na
2
S
4
O
6
+2NaI
Iodine is reduced and sodium thiosulphate is oxidized.
<span>You must multiply the bond enthalpy by each broken or formed bond.
The C - H bond = 414k Joules/ mol, but that is only applicable per bond.
The C3H8 molecule has 8*C-H bonds that have to break. You have to account all the bonds that break and form to get the DH for the reaction.
Because of the Lewis structure of Propane C3h8 you only use 8 in </span><span>c3h8 has 3-C and 8-C.</span>
A phospholipid has a charged head and an uncharged tail.
Explanation:
100 liter because it is measured
