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user100 [1]
3 years ago
5

What are the first 9 nonzero multipes of 7?

Mathematics
2 answers:
Alecsey [184]3 years ago
7 0

Answer:

7, 14, 21, 28, 35, 42, 49, 56, 63

Step-by-step explanation

Marrrta [24]3 years ago
5 0
7, 14, 21, 28, 35, 42, 49, 56, 63
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-15+3-7 is greater than less than or equal to -9-1+16
lisov135 [29]

Answer:less than

Step-by-step explanation:

-15+3-7=-19

-9-1+16=6

A positive will always be bigger than a negative

5 0
3 years ago
Read 2 more answers
Simplify the following expression. 2^2 • 2^3
sesenic [268]

Answer:

4 × 6

Step-by-step explanation:

2^2= 4 or 2 × 2= 4

2^3= 6 or 2 × 2 × 2= 6

So, 4 × 6

8 0
2 years ago
What is the completely factored form of d4-8d2+16
Cloud [144]
Solution:

1) Rewrite it in the form {a}^{2}-2ab+{b}^{2}, where a={d}^{2} and b=4
{({d}^{2})}^{2}-2({d}^{2})(4)+{4}^{2}

2) Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}
{({d}^{2}-4)}^{2}

3) Rewrite {d}^{2}-4​ in the form {a}^{2}-{b}^{2}​​ , where a=d and b=2
{({d}^{2}-{2}^{2})}^{2}
​​
4) Use Difference of Squares: {a}^{2}-{b}^{2}=(a+b)(a-b)
​{((d+2)(d-2))}^{2}

5) Use Multiplication Distributive Property: {(xy)}^{a}={x}^{a}{y}^{a}
{(d+2)}^{2}{(d-2)}^{2}

Done!
8 0
3 years ago
Read 2 more answers
A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc
Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be 2x.

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

6\%=\frac{6}{100}=0.06

10\%=\frac{10}{100}=0.10

Amount of interest earned from lower-yielding account: 2x(0.06)=0.12x.

Amount of interest earned from higher-yielding account: x(0.10)=0.10x.

0.12x+0.10x=6600

Let us solve for x.

0.22x=6600

\frac{0.22x}{0.22}=\frac{6600}{0.22}

x=30,000

Therefore, the man invested $30,000 at 10%.

Amount invested in the lower-yielding account would be 2x\Rightarrow 2(30,000)=60,000.

Therefore, the man invested $60,000 at 6%.

8 0
2 years ago
What's the value of x if 7x-5 =5x+23
olya-2409 [2.1K]
7x-5=5x+23
7x-5x=23+5
2x=28
x=28/2
x=14
6 0
3 years ago
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