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jeyben [28]
3 years ago
15

Help Please !!!

Physics
2 answers:
Deffense [45]3 years ago
6 0
1.
<span>The Galápagos Islands contain more different species than any comparable place on the earth.
2.</span>
<span>Their aim is to prevent extinctions.
3.</span>
<span>a gas that absorbs and re-releases heat radiated by the earth
4</span>
<span>acid rain
5.</span>
<span>stratospheric ozone
6</span>
<span>methane
7.</span>
landfill
8.
<span>catalytic converter</span>

Vlada [557]3 years ago
6 0

Answer:

Q1- The correct answer is: Many species unique to the islands may become extinct. Those species won't have another place like Galápagos to develop themselves, ceasing to exist then.

Q2- The correct answer is: Their aim is to prevent extinctions. By preventing it, diversity is protected in different places.

Q3- The correct answer is: a gas that absorbs and re-releases heat radiated by the earth. Those gases are very harmful for our atmosphere when in excessively high amounts, because they increase the greenhouse effect.

Q4- The correct answer is: acid rain. Sulfur can mix with water particles on air and be condensed into rain, lowering water's pH and making it acid.

Q5- The correct answer is: stratospheric ozone. It protects us from sun radiation and also transfers heat for us.

Q6- The correct answer is: greenhouse gases. Those absorb and re-release the heat in our planet, increasing global warming effects.

Q7- The correct answer is: enacting air pollution laws. The smog caused by it harmed thousands of people, and this aspect wasn't controled until then.

Q8- The correct answer is: water vapor. It dissipates heat, and doesn't absorb and re-release it.

Q9- The correct answer is: landfill. The other means of disposal aren't as common as landfill.

Q10- The correct answer is: catalytic converter. It transforms the gaseous emissions into other products by chemical reactions.

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An object of mass 6.00 kg falls with an aceleration of 8.00 m/s2. The magnitude of air resitance must be ____ N
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7 0
3 years ago
(b) The distance of mass from mass A if there is no gravitational force acted on C
shepuryov [24]

Answer:

(a) The force, acting on object 'C' is approximately 2.66972 × 10⁻¹⁰ Newtons

(b) The distance of 'C' from 'A', in the direction particle 'B' if there is no  meters gravitational force acting on 'C' is appromimately 0.829 meters or 1.877 meters

Explanation:

The given parameters are;

The mass of particle, A, m₁ = 2 kg

The mass of particle, B, m₂ = 0.3 kg

The mass of particle, C, m₃ = 0.05 kg

The distance between particle 'A' and particle 'B', r₁ = 0.15 m

The distance between particle 'B' and particle 'C', r₂ = 0.05 m

(a) The gravitational force, 'F', is given as follows;

F =G \times \dfrac{m_{1} \times m_{2}}{r^{2}}

Where;

F = The force between the two masses

G = The gravitation constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m₁ = The mass of object 1

m₂ = The mass of object 2

If 'C' is placed at 0.05 m from 'B', we have;

F₂₃ =  6.67430 × 10⁻¹¹ × 0.05 × 0.3/(0.05²) ≈ 4.00458 × 10⁻¹⁰

The gravitational force between force between particle 'B' and particle 'C', F₂₃ = 4.00458 × 10⁻¹⁰ N (towards the right)

F₁₃ =  6.67430 × 10⁻¹¹ × 0.05 × 2/(0.1²) ≈ × 10⁻¹⁰

The gravitational force between force between particle 'A' and particle 'B', F₁₃ = 6.6743 × 10⁻¹⁰ N (towards the left)

The force, 'F', acting on object 'C' = F₁₃ - F₂₃

F = (6.6743 - 4.00458) × 10⁻¹⁰ = 2.66972 × 10⁻¹⁰ N

The force, acting on object 'C' ≈ 2.66972 × 10⁻¹⁰ N

(b), When there is no gravitational force acting on 'C', let the distance of 'C' from 'A' = x

We have;

F₂₃ = F₁₂

F_{23} =G \times \dfrac{m_{1} \times m_{2}}{r_1^{2}} = F_{13} =G \times \dfrac{m_{1} \times m_{3}}{r_2^{2}}

By plugging in the values and removing like terms, we get;

\dfrac{0.3 \times 0.05}{(1.15 - x)^{2}}  = \dfrac{2 \times 0.05}{x^2}

(1.15 - x)² × 2 × 0.05 = 0.3 × 0.05 × x²

0.1·x² - 0.23·x + 1.3225 = 0.015·x²

0.1·x² - 0.23·x + 1.3225 - 0.015·x² = 0

0.085·x² - 0.23·x + 0.13225= 0

x = (0.23± √((-0.23)² - 4 × 0.085 × ( 0.13225)))/(2 × 0.085))

x ≈ 0.829, or x ≈ 1.877

Therefore, the distance of 'C' from 'A', if there is no gravitational force acting on 'C', x ≈ 0.829 m, or x = 1.877 m, in the direction of 'B'

7 0
3 years ago
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