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2 years ago

Help Please !!!

2 answers:

6 0

1.
The Galápagos Islands contain more different species than any comparable place on the earth.
2.
Their aim is to prevent extinctions.
3.
a gas that absorbs and re-releases heat radiated by the earth
4
acid rain
5.
stratospheric ozone
6
methane
7.
landfill
8.
catalytic converter

Vlada [557]2 years ago

6 0

Answer:

Q1- The correct answer is: Many species unique to the islands may become extinct. Those species won't have another place like Galápagos to develop themselves, ceasing to exist then.

Q2- The correct answer is: Their aim is to prevent extinctions. By preventing it, diversity is protected in different places.

Q3- The correct answer is: a gas that absorbs and re-releases heat radiated by the earth. Those gases are very harmful for our atmosphere when in excessively high amounts, because they increase the greenhouse effect.

Q4- The correct answer is: acid rain. Sulfur can mix with water particles on air and be condensed into rain, lowering water's pH and making it acid.

Q5- The correct answer is: stratospheric ozone. It protects us from sun radiation and also transfers heat for us.

Q6- The correct answer is: greenhouse gases. Those absorb and re-release the heat in our planet, increasing global warming effects.

Q7- The correct answer is: enacting air pollution laws. The smog caused by it harmed thousands of people, and this aspect wasn't controled until then.

Q8- The correct answer is: water vapor. It dissipates heat, and doesn't absorb and re-release it.

Q9- The correct answer is: landfill. The other means of disposal aren't as common as landfill.

Q10- The correct answer is: catalytic converter. It transforms the gaseous emissions into other products by chemical reactions.

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3 years ago

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Answer:

The answer is " $q=0.0945\,C$ ".

Explanation:

Its minimum velocity energy is provided whenever the satellite(charge 4 q) becomes 15 m far below the square center generated by the electrode (charge q).

$U_i=\frac{1}{4\pi\epsilon_0} \times \frac{4\times4q^2}{\sqrt{(15)^2+(5/\sqrt2)^2}}$

It's ultimate energy capacity whenever the satellite is now in the middle of the electric squares:

$U_f=\frac{1}{4\pi\epsilon_0}\ \times \frac{4\times4q^2}{( \frac{5}{\sqrt{2}})}$

Potential energy shifts:

$= U_f -U_i \\\\ =\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{\sqrt2}{5}-\frac{1}{\sqrt{(15)^2+( \frac{5}{\sqrt{2})^2)}}\right ) \\\\ =\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{\sqrt2}{5}-\frac{1}{ 15 +( \frac{5}{2})}}\right )\\\\ =\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{\sqrt2}{5}-\frac{1}{ (\frac{30+5}{2})}}\right )\\\\$

$=\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{\sqrt2}{5}-\frac{1}{ (\frac{35}{2})}}\right )\\\\=\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{\sqrt2}{5}-\frac{1}{17.5}}\right )\\\\ =\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{ 24.74- 5 }{87.5}}\right )\\\\ =\frac{16q^2}{4\pi\epsilon_0}\left ( \frac{ 19.74- 5 }{87.5}}\right )\\\\ =\frac{4q^2}{\pi\epsilon_0}\left ( 0.2256 }\right )\\\\= \frac{0.28 \times q^2}{ \epsilon_0}\\\\=q^2\times31.35 \times10^9\,J$

Now that's the energy necessary to lift a satellite of 100 kg to 300 km across the surface of the earth.

$=\frac{GMm}{R}-\frac{GMm}{R+h} \\\\=(6.67\times10^{-11}\times6.0\times10^{24}\times100)\left(\frac{1}{6400\times1000}-\frac{1}{6700\times1000} \right ) \\\\ =(6.67\times10^{-11}\times6.0\times10^{26})\left(\frac{1}{64\times10^{5}}-\frac{1}{67\times10^{5}} \right ) \\\\=(6.67\times6.0\times10^{15})\left(\frac{67 \times 10^{5} - 64 \times 10^{5} }{ 4,228 \times10^{5}} \right ) \\\\$

$=( 40.02\times10^{15})\left(\frac{3 \times 10^{5}}{ 4,228 \times10^{5}} \right ) \\\\ =40.02 \times10^{15} \times 0.0007 \\\\$

$\\\\ =0.02799\times10^{10}\,J \\\\= q^2\times31.35\times10^{9} \\\\ =0.02799\times10^{10} \\\\q=0.0945\,C$

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