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3 years ago

A object travels at constant negative acceleration. What does the graph of the object's velocity as a fun

1 answer:

7 0

Constant = straight line
“Travels at constant negative acc.”
Which is negative slope

Solution: B. Straight line w/ neg. slope

You might be interested in

Which is the average acceleration during the time Interval 0 seconds 10 seconds?

weqwewe [10]

Average acceleration = (change in speed) / (time for the change)

In this case . . .

Average acceleration = (speed at the end - speed at the beginning)/10sec.

We can't be any more specific without knowing the difference
between the beginning speed and the ending speed.

3 0

3 years ago

Uma chapa metálica, com um furo central de diâmetro "d", é aquecida dentro de um forno. Com o aumento da temperatura, podemos af

Tatiana [17]

Answer: O furo diminui enquanto a chapa aumenta a sua dimensão.

(The diameter decreases and the dimensions of the metal increases)

Explanation:

I will answer in English:

Here we have a piece of metal with a small hole on it, that is heated in a hoven.

We know that when a piece of metal is heated, it will expand (the density decreases, so the dimensions of the piece of metal increase).

Now, particularly, the hole will also expand but inwards, as each "extreme" of the piece of metal, will expand into where it has less resistance, so it will expand in the region where there is no material. This "inwards" expansion is why the diameter of the hole will decrease.

4 0

3 years ago

A solid sphere of radius 40.0cm has a total positive charge of 26.0μC uniformly distributed throughout its volume. Calculate the

Rudiy27

The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C

R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m

$Q\;(\text{total charge of the solid sphere})=(26\;\mathrm{\mu C})\left(\dfrac{1\;\mathrm{C}}{10^6\;\mathrm{\mu C}} \right)={26\times 10^{-6}\;\mathrm{C}}$

Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:

$E=\dfrac{Q}{4\pi\epsilon_0 r^2}$

Substitute numerical values:

$E&=\dfrac{24\times 10^{-6}}{4\pi (8.8542\times 10^{-12})(0.6)}\\ &={6.49\times 10^5\;\mathrm{N/C}\;\text{directed radially outward}}}$

The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.

As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).

Learn more about Gaussian sphere here:

brainly.com/question/2004529

#SPJ4

6 0

2 years ago

A neutral atom possesses an atomic number of 13 and an atomic mass of 27. Three electrons are lost. From what region of the atom

slega [8]

The atomic number of the atom is 13. This means that its electronic configuration is (2 8 3) or in other words:
1s2, 2s2, 2p6, 3s2, 3p1

If three electrons are lost, then these electrons are removed from the outermost level.
In our case, electrons are removed from the third energy level (one electron is removed from the 3p orbital and two electrons are removed from the 3s orbital).

8 0

3 years ago

Suppose two children push horizontally, but in exactly opposite directions, on a third child in a wagon. The first child exerts

wolverine [178]

Answer:

0.304 m/s2

Explanation:

If the first child is pushing with a force of 69N to the right and the 2nd child is pushing with a force of 91N to the left. Then the net pushing force is 91 - 69 = 22 N to the left. Subtracted by 15N friction force then the system of interest is subjected to F = 7 N net force tot he left.

We can use Newton's 2nd law to calculate the net acceleration of the system

$a = F/m = 7 / 23 = 0.304 m/s^2$

5 0

3 years ago