Un recipiente contiene 224 dm3 de Ozono de masa 4.561 Kg a 51.09 grados celsius. Calcula la presión del Ozono
1 answer:
Answer:
Por lo tanto, la presión del ozono es:
Explanation:
Podemos usar la ecuacion de los gases ideales;
(1)
Tenemos:
El volumen V = 224 dm³ = 224 L
La temperatura T = 51.09 C = 324.09 K
La masa es m = 4.561 kg
Lo necesitamos ahora es calvular n que es el numero de moles;
recordemos que el peso molecular del ozono M = 48 g/mol.
Finalmente, usando la ecuacion 1 despejamos la presion P
Por lo tanto, la presion del ozono es:
Espero te haya ayudado!
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Answer:
(a)
(b)
Explanation:
Parameter given:
Electric field, E =
(a) Electric force is given (in terms of electric field) as a product of electric charge and electric field.
Mathematically:
Electric charge, q, of an electron =
(b) This electrostatic force causes the electron to accelerate with an equivalent force:
F = -ma
where m = mass of an electron
a = acceleration of electron
(Note: the force is negative cos the direction of the force is opposite the direction of the electron)
Therefore:
Mass, m, of an electron =
=>
The acceleration of the electron is