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DanielleElmas [232]
3 years ago
15

Un recipiente contiene 224 dm3 de Ozono de masa 4.561 Kg a 51.09 grados celsius. Calcula la presión del Ozono

Physics
1 answer:
kari74 [83]2 years ago
5 0

Answer:

Por lo tanto, la presión del ozono es:

P=0.011\: atm  

Explanation:

Podemos usar la ecuacion de los gases ideales;

PV=nRT (1)

Tenemos:

El volumen V = 224 dm³ = 224 L

La temperatura T = 51.09 C = 324.09 K

La masa es m = 4.561 kg

Lo necesitamos ahora es calvular n que es el numero de moles;

recordemos que el peso molecular del ozono M = 48 g/mol.

n=\frac{m}{M}=\frac{4.561}{48}=0.095\: mol

Finalmente, usando la ecuacion 1 despejamos la presion P

P=\frac{nRT}{V}

P=\frac{0.095*0.082*324.09}{224}  

Por lo tanto, la presion del ozono es:

P=0.011\: atm  

Espero te haya ayudado!

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\theta=\cos^{-1}\dfrac{(-4.10i + 3.30j + 5.40k)\cdot(2.70i - 2.90j + 5.50k)}{7.54\times6.778})

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Hence, (a). The work done on the object by the force in the 5.40 s interval is 41.67 J.

(b). The average power due to the force during that interval is 7.71 Watt.

(c).  The angle between vectors is 79.7°

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