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sukhopar [10]
3 years ago
9

The track of a roller coaster is shown below. At which point will the riders experience centripetal acceleration?

Physics
2 answers:
bulgar [2K]3 years ago
8 0

<u>The answer to this question is Y</u>

Hope this helps :)

valentinak56 [21]3 years ago
4 0

Centripetal acceleration is applied in circular motion. Y is the point on the track that most closely resembles a circular path for the roller coaster.

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1. The current in a wire is 0.72A. Calculate the charge that passes through the wire in; a. 4 s b. 60 s c. 180 s d. 7 s e. 0.5 s
Vlad [161]
Let current be I, charge be Q and time be t.
Here we are provided with,
I = 0.72A
t = 4s / 60s / 180s / 7s / 0.5s
We know,
I = Q/t

Case I
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When, t = 4s
0.72 = Q/4
Q = 0.72 * 4 = 2.88C

Case II
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When, t = 60s
0.72 = Q/60
Q = 0.72 * 60 = 43.2C

Case III
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When, t = 180s
0.72 = Q/180
Q = 0.72 * 180 = 129.6C

Case IV
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When, t = 7s
0.72 = Q/7
Q = 0.72 * 7 = 5.04C

Case V
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When, t = 0.5s
0.72 = Q/0.5
Q = 0.72 * 0.5 = 0.36C
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3 years ago
un avión aterriza en la superficie de un portaaviones a 50 m/s y se detiene por completo en 120 metros, ¿cuál es la aceleración
sergejj [24]

Answer:

La aceleración necesaria para detener el avión es - 10.42 m/s².

Explanation:

Un movimiento uniformemente acelerado (M.U.A) es aquél cuya aceleración es constante y la velocidad de un objeto cambia a medida que el movimiento evoluciona.

Siendo la aceleración "a" el cambio de velocidad al tiempo transcurrido en un punto A a B, la velocidad inicial la velocidad que tiene un cuerpo al iniciar su movimiento en un período de tiempo y la velocidad final la velocidad que tiene un cuerpo al finalizar su movimiento en un período de tiempo, entonces en  M.U.A se cumple:

Vf² - Vo² = 2*a*d

donde:

  • Vf: Velocidad final
  • Vo: Velocidad inicial
  • a: Aceleración
  • d: Distancia recorrida

En este  caso:

  • Vf: 0 m/s, porque el avión se detiene
  • Vo: 50 m/s
  • a: ?
  • d: 120 m

Reemplazando:

(0 m/s)² - (50 m/s)² = 2*a*120 m

Resolviendo:

a=\frac{(0 m/s)^{2} -(50 m/s)^{2} }{2*120 m}

a= - 10.42 m/s²

<u><em>La aceleración necesaria para detener el avión es - 10.42 m/s².</em></u>

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