1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sukhopar [10]
3 years ago
9

The track of a roller coaster is shown below. At which point will the riders experience centripetal acceleration?

Physics
2 answers:
bulgar [2K]3 years ago
8 0

<u>The answer to this question is Y</u>

Hope this helps :)

valentinak56 [21]3 years ago
4 0

Centripetal acceleration is applied in circular motion. Y is the point on the track that most closely resembles a circular path for the roller coaster.

You might be interested in
Why one part of the earth's surface is arid and dry and a nearby part is lush and wet is explained by the term?
Darina [25.2K]
The process that explains why one part of the earth's surface is arid and dry and a nearby part is lush and wet is areal differentiation. It is<span> an approach to geography that shows </span>the dependence of the distribution of physical and human phenomena and the relation  to each other from the physical location. Areal integration on the other hand is the approach that studies how places interact with each other.
8 0
3 years ago
Plz hurry How fast can work be done by a 7 horsepower engine?
den301095 [7]

Answer:

It will go about 45-50 mph.

Explanation:

Depending on what you are hauling.

7 0
3 years ago
Read 2 more answers
A glider with mass m = 0.230 kg sits on a frictionless horizontal air track, connected to a spring with force constant k = 4.50
loris [4]

Answer

given,

mass of glider = 0.23 Kg

spring constant = k = 4.50 N/m

spring stretched to 0.130 m

The springs potential energy =

 U = \dfrac{1}{2}kx^2

 U = \dfrac{1}{2}\times 4.5 \times 0.13^2

        U = 0.038 J

at x = 0,the only energy will be kinetic .

 \dfrac{1}{2}mv^2=0.038

 \dfrac{1}{2}\times 0.23 \times v^2=0.038

         v² = 0.3304

         v = 0.575 m/s

displacement of the glider

      using conservation of energy

 \dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

 x =v\sqrt{\dfrac{m}{k}}

 x =3\times \sqrt{\dfrac{0.23}{4.5}}

        x = 0.678 m

8 0
3 years ago
what will be the moment of inertia of a body if it rotates at a uniform rate of 10rad/sec^2 by a torque of 120Nm?​
Naya [18.7K]

Answer:

12 kgm²

Explanation:

here angular acceleration = 10rad/sec²

torque= 120Nm

moment of inertia=?

we know,

torque= angular acceleration× moment of Inertia

or, moment of inertia = torque/angular acceleration

= 120/10

= 12kgm²

7 0
3 years ago
What is the SI (metric) unit of FORCE?<br><br> A. meter<br> B. newton
Tresset [83]

What is the SI (metric) unit of FORCE?

  • B. newton

with symbol ( N )

All the best !

4 0
2 years ago
Read 2 more answers
Other questions:
  • If a system absorbs heat and also does work on its surroundings its energy
    8·1 answer
  • Katniss, an alien from another planet, shoots an arrow straight into the air 2.4 meters from the ground at 36 meters per second.
    8·1 answer
  • spring is compressed 4.2 cm. If a box is placed at the end of the compressed spring, and let go, how far up the ramp will the sp
    7·1 answer
  • 1. Determina el momento que produce una fuerza de 7 N tangente a una rueda de un metro de diámetro, sabiendo que el punto de apl
    5·1 answer
  • Explain why do conductors and insulators are both required to construct electrical wiring in your home
    10·1 answer
  • Which of the following is an example of a renewable natural resource?
    14·1 answer
  • When playing a game of disc golf, each throw to your target is considered to be a O Point O Stroke O Hit O Toss​
    11·1 answer
  • 4. What is the momentum of a 70 kg object traveling at 20 m/s?
    7·1 answer
  • What is the electrical power when the current is 20 amps and the voltage is 15 volts? *
    14·1 answer
  • The answer is not B.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!