The mass of a dust particle would be measured in?
1 answer:
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<u>Answer:</u> The particle released in the given reaction is one alpha particle
<u>Explanation:</u>
In a nuclear reaction, the total mass and total atomic number remains the same.
For the given fission reaction:
- <u>To calculate A:</u>
Total mass on reactant side = total mass on product side
222 = A + 218
A = 4
- <u>To calculate Z:</u>
Total atomic number on reactant side = total atomic number on product side
86 = Z + 84
Z = 2
The isotopic symbol of unknown element is . Another name of helium atom is alpha particle.
Hence, the particle released in the given reaction is one alpha particle
Answer:
See explanation and image attached
Explanation:
The standard cell potential at 298 K is given by;
E°cathode - E°anode
Hence;
E°cell = 0.34 V - (-0.76 V)
E°cell = 0.34 V + 0.76 V
E°cell = 1.1 V
To reduce Zn^2+ to Zn then Zn must be the cathode, hence;
E°cell = (-0.76 V) - 0.34 V
E°cell = -1.1 V
