Distance = 170 km Displacement = 30 km East Speed = 56-2/3 km/hr Velocity = 10 km/hr East
There are several differences between<span> a </span>physical and chemical change<span> in matter or substances. A </span>physical change<span> in a substance doesn't </span>change<span> what the substance is. In a </span>chemical change<span> where there is a </span>chemical<span> reaction, a new substance is formed and energy is either given off or absorbed.</span>
Answer:
Part A: 16.1 V
Part B: 20.5 V
Part C: 21.5%
Explanation:
The voltmeter is in parallel with the 4.5-kΩ resistor and the combination is in series with the 6.5-kΩ resistor. The equivalent resistance of the parallel combination is given as
Part A
The voltmeter reading is the potential difference across the parallel combination. This is found by using the voltage-divider rule.
Part B
Without the voltmeter, the potential difference across the 4.5-kΩ resistor is found using the same rule as above:
Part C
The error in % is given by
Answer:
27.6 m/s
5.64 s
Explanation:
Given:
Δy = 39 m
a = -9.8 m/s²
v = 0 m/s
Find: v₀
v² = v₀² + 2aΔy
(0 m/s)² = v₀² + 2 (-9.8 m/s²) (39 m)
v₀ = 27.6 m/s
Find: 2t
Δy = vt − ½ at²
(39 m) = (0 m/s) t − ½ (-9.8 m/s²) t²
t = 2.82 s
2t = 5.64 s