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2 years ago

Tp-18 what should you do when operating a boat in large waves and high wind?

Physics

1 answer:

deff fn [24]2 years ago

5 0

1) Try to head into the waves at some slight angle and the speed of the boat should be reduced.

2) In order to ride up and over the waves, the speed of the boat should be slow.

3) The less the speed of the boat, and the less strain will be put on the hull and superstructure.

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The___ of a mirror's surface determines the type of image it forms.

Kobotan [32]

I believe Virtual not really sure

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2 years ago

One student runs with a velocity of +10 m/s while a second student runs with a velocity of –10 m/s. Which student has the faster

larisa86 [58]

Answer:

The one with the faster velocity is the one with a velocity of -10m/s

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3 years ago

1. What are the 3 spheres of Earth?

dolphi86 [110]

they are the lithosphere (land), hydrosphere (water), biosphere (living things), and atmosphere (air).

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2 years ago

Below is an "oracle" function. An oracle function is a function presented interactively. When you type in a t value, and press t

Bingel [31]

Answer:

The rate of change of height with respect to time is -10.64 feet/sec

Explanation:

Given that,

There are three lines, so you can calculate three different values of the function at one time.

The function f(t) represents the height in feet of a ball thrown into the air, t seconds after it has been thrown.

Given table is,

Time t = 0, 1, 1,02

Function is, $F(t)=-3.053113177191196\times10^{-18},6.000000000000134, 6.41760000000015$

We need to calculate the initial height of ball

Using equation of motion

$h=h_{0}+ut-\dfrac{1}{2}gt^2$

Where, h₀ = initial height

u = initial velocity

t = time

g = acceleration due to gravity

At t = 0,

Put the value into the formula

$-3.053113177191196\times10^{-18}=h_{0}+0-0$

$h_{0}=-3.053113177191196\times10^{-18}$

We need to calculate the height of ball at t = 1

Using equation of motion

$h_{1}=h_{0}+u_{0}t-\dfrac{1}{2}gt^2$

Put the value in the equation

$6.000000000000134=-3.053113177191196\times10^{-18}+u-\dfrac{1}{2}\times32$

$6.000000000000134+3.053113177191196\times10^{-18}+16=u_{0}$

$u_{0}=22\ feet/s$

Velocity is the rate of change of height with respect to time

So, velocity at 1.02 sec is given

We need to calculate the height

Using equation of motion

$h=ut-\dfrac{1}{2}gt^2$

On differentiating w.r.to t

$h'(t)=u-\dfrac{1}{2}g(2t)$

Put the value into the formula

$h'(t)=22-\times32\times(1.02)$

$h'(t)=-10.64\ feet/sec$

Hence, The rate of change of height with respect to time is -10.64 feet/sec.

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2 years ago

¿Que es un átomo???????

disa [49]

Un átomo es una porción material menor de un elemento químico que interviene en las reacciones químicas y posee las propiedades características de dicho elemento.

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2 years ago