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1 year ago

7. Using Analogies Explain how the behavior

1 answer:

7 0

The relative motion of gaseous particles increases with increase in the temperature of the gas molecules just like the motion of popcorn in a popper increases when heat is applied to the popper.

<h3>What is kinetic theory of gas?</h3>

The kinetic theory of gases or matter states that matter consists of tiny particles which are constant motion, colliding with one another and with walls of the containing vessels.

Just like a popcorn in a popcorn popper pops when heat is applied to the popper, gases contained in a cylinder increases their speed when they acquire more kinetic energy as the temperature of the cylinder increases.

Thus, the motion of gas particles depends on the temperature of the containing vessel so also does the random motion of popcorn depends on the temperature of the popper.

Learn more about kinetic theory of gases here: brainly.com/question/11067389

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Alkali metals _____.

Lyrx [107]

I think the answer is C

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3 years ago

A 1.00 kg object is attached to a horizontal spring. the spring is initially stretched by 0.500 m, and the object is released fr

valina [46]

The spring is initially stretched, and the mass released from rest (v=0). The next time the speed becomes zero again is when the spring is fully compressed, and the mass is on the opposite side of the spring with respect to its equilibrium position, after a time t=0.100 s. This corresponds to half oscillation of the system. Therefore, the period of a full oscillation of the system is
$T=2 t = 2 \cdot 0.100 s = 0.200 s$
Which means that the frequency is
$f= \frac{1}{T}= \frac{1}{0.200 s}=5 Hz$
and the angular frequency is
$\omega=2 \pi f = 2 \pi (5 Hz)=31.4 rad/s$

In a spring-mass system, the maximum velocity of the object is given by
$v_{max} = A \omega$
where A is the amplitude of the oscillation. In our problem, the amplitude of the motion corresponds to the initial displacement of the object (A=0.500 m), therefore the maximum velocity is
$v_{max} = A \omega = (0.500 m)(31.4 rad/s)= 15.7 m/s$

6 0

3 years ago

2. If a cyclist in the Tour de France traveled southwest a distance of 12,250 meters in one hour, what would the velocity of the

Luda [366]

Answer:

12,25 km/h

≈ 3,4 m/s

Explanation:

v = d/t

= 12250m/h

= 12,25km/h

or

v = d/t

= 12250m/h

1h = 60m×60s = 3600s

= 12250m/3600s

≈ 3,4 m/s

5 0

3 years ago

. Friction is a rubbing force that ___________ a spinning yo-yo.

Advocard [28]

The yo-yo speeds up when you rub it

3 0

3 years ago

Read 2 more answers

If τ=r×F then F.τ is equal

Mademuasel [1]

Yes that is correct.

4 0

3 years ago