If a rock is thrown upward on the planet Mars with a velocity of 10 ms, its height in meters seconds later is given by (a) Find
1 answer:
Answer:
2) S(Δt)=So+g(Δt)
Explanation:
I think the equation they gave you for the Height upon time in seconds it's (1), where if you see, you will find the gravity, that you should multiply by 2 because, its divided by two in (1) (that should be your (a)), then, once you find your gravity, you can use the equation (2) to know the Final Speed replacing g , at the time asked, remember that g is gravity, and Δt is the: final time- initial time.
so in the [1,2] interval of time, your Δt=1s, and in [1,1.5] is Δt=0,5s.
i hoped it helped you even though i cant give you the exact answer right now.
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Answer:
temperature at 326.44 K system achieve equilibrium
Explanation:
given data
mass of block of ice = 4.6 kg
temperature = 263 K
thermal contact = 15.7-kg
specific heat of silver cAg = 233 J/kg-K
initially temperature = 1052 K
to find out
what temperature will the system achieve equilibrium
solution
first we consider final temperature of the system is T
we know that specific heat of water (C w) = 4186 J(kg K)
and
specific heat of ice ( C i ) = 2030 J/(kg K)
and
latent heat of fusion of ice ( Lf ) = 3.33 × J/kg
and we know that system is insulated
so heat lost by silver = heat generated by ice .................1
so we can say
mass of silver × specific heat of silver × ( initial temp - final temp ) = mass of ice × specific heat of ice × ( ice temp ) + mass of ice × latent heat of fusion of ice + mass of ice × specific heat of water × (final temperature )
put here value we get
mass of silver × specific heat of silver × ( initial temp - final temp ) = mass of ice × specific heat of ice × ( ice temp ) + mass of ice × latent heat of fusion of ice + mass of ice × specific heat of water × (final temperature )
15.7 × 233 × ( 1052 - T ) = 4.6 × 2030 × 10 + 4.6 × 3.33 × + 4.6 × 4286 × ( T - 273 )
solve we get
T = 326.44 K
so temperature at 326.44 K system achieve equilibrium
Answer:
256.68m
Explanation:
that is the procedure above
Answer:
t = 5.59x10⁴ y
Explanation:
To calculate the time for the ¹⁴C drops to 1.02 decays/h, we need to use the next equation:
(1)
<em>where : is the number of decays with time, A₀: is the initial activity, λ: is the decay constant and t: is the time.</em>
To find A₀ we can use the following equation:
(2)
<em>where N₀: is the initial number of particles of ¹⁴C in the 1.03g of the trees carbon </em>
From equation (2), the N₀ of the ¹⁴C in the trees carbon can be calculated as follows:
<em>where : is the tree's carbon mass,
: is the Avogadro's number and
: is the ¹²C mass. </em>
Similarly, from equation (2) λ is:
<em>where t 1/2: is the half-life of ¹⁴C= 5700 years </em>
So, the initial activity A₀ is:
Finally, we can calculate the time from equation (1):
I hope it helps you!