<span>Data:
mass =
110-g bullet
d = 0.636 m
Force =
13500 + 11000x - 25750x^2, newtons.
a) Work, W
W = ∫( F* )(dx) =∫[13500+ 11000x - 25750x^2] (dx) =
W = 13500x + 5500x^2 - 8583.33 x^3 ] from 0 to 0.636 =
W = 8602.6 joule
b) x= 1.02 m
</span><span><span>W = 13500x + 5500x^2 - 8583.33 x^3 ] from</span> 0 to 1.02
W = 10383.5
c) %
[W in b / W in a] = 10383.5 / 8602.6 = 1.21 => W in b is 21% more than work in a.
</span>
Answer:
11.0 kg m/s
Explanation:
The impulse exerted on the cart is equal to its change in momentum:

where
m = 5.0 kg is the mass of the cart
is its change in speed
Substituting numbers into the equation, we find

Answer:

Explanation:
Hello,
In this case, since we compute the required energy via:

Whereas m is the mass which here is 70 g, C the specific heat which for water is 4.184 J/(g°C) and ΔT is the temperature difference which is:

Therefore, the energy turns out:

Best regards.
Answer:
Option A
Solution:
As per the question:
The distance covered by the woman in the North direction, d = 3000 m
Time taken to travel in North direction, t = 25.0 min = 1500 s
Velocity of woman in the south direction, v = 2.00 m/s
Time taken in the south direction, t' = 60.0 min = 3600 s
Now,
The distance covered in the south direction, d' = vt' = 
Now, the total displacement is given by:
D = d' - d = 7200 - 3000 = 4200 m in South
(a) Average velocity of the woman in the whole journey is given by:

≈ 0.824 m/s South
Answer:
Yes.
Explanation:
The pressure varies as per the depth of the container