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storchak [24]
3 years ago
12

Ms. Huynh spent $640 to stay in a hotel for four nights. Each night she spent x dollars on the hotel room as well as a $15 parki

ng fee per day. The equation below represents the total amount, in dollars, that Ms. Huynh spent on her hotel. 4(x + 15) = 640 How much money did the hotel room cost for one night, excluding the parking fee?
Mathematics
2 answers:
andrey2020 [161]3 years ago
8 0

Answer:

175 a night

Step-by-step explanation:

640/4=160+15=175

ludmilkaskok [199]3 years ago
3 0

Answer: $140

Step-by-step explanation:

First you need to find a way to isolate your variable (X). To do this you must divide 640 by 4. Next subtract 15 from each side. This will lead to x=140

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Answer:

1. x^2-9x+18

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Step-by-step explanation:

1. (x-3)(x-6)

x^2 - 6x - 3x +18 = x^2-9x+18

2. (2x+4)(x-4)

2x^2-8x+4x-16 = 2x^2-4x-16

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3 years ago
Which ordered pair is included in the solution set to the following system? y > x2 + 3 y < x2 – 3x + 2 (–2, 8) (0, 2) (0,
I am Lyosha [343]

The ordered pair that is a solution of the system is (-2, 8).

<h3>Which ordered pair is included in the solution set to the following system?</h3>

Here we have the system of inequalities:

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y < x² - 3x + 2

To check which points are solutions of the system, we can just evaluate both inequalities in the given points and see if they are true.

For example, for the first point (-2, 8) if we evaluate it in the two inequalities we get:

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As we can see, both inequalities are true. So we conclude that (-2, 8) is the solution.

(if you use any other of the 3 points you will see that at least one of the inequalities becomes false).

If you want to learn more about inequalities:

brainly.com/question/18881247

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umka21 [38]

c = cost per pound of chocolate chips

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\bf \stackrel{\textit{3 lbs of "c"}}{3c}+\stackrel{\textit{5 lbs of "w"}}{5w}~~=~~\stackrel{\textit{costs}}{15} \\\\\\ \stackrel{\textit{12 lbs of "c"}}{12c}+\stackrel{\textit{2 lbs of "w"}}{2w}~~=~~\stackrel{\textit{costs}}{33} \end{cases}\qquad \impliedby \textit{let's use elimination} \\\\[-0.35em] ~\dotfill\\\\ \begin{array}{llccccccl} 3c+5w=15&\times (-4)\implies &-12c&+&-20w&=&-60\\ 12c+2w=33&&12c&+&2w&=&33\\ \cline{3-7}\\ &&0&&-18w&=&-27 \end{array}

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