Assuming linear.
if k is at (3,4) and j is at (-8,7)
set. (y1,x1) and(y2,x2)
[(y2-y1),(x2-x1)]
[(-8-3),(7-4)]
distance from k to j is (-11,3)
now take coordinates of j and distance from. k->j and add them to get coordinate for L
[(-11+(-8)),(7+3)]= (-19,10)=L
Step-by-step explanation:
Our coordinates are (6, 0) and (0, -3).
We can use the formula (y₂-y₁)/(x₂-x₁) to find the slope-intercept form (y=mx+b)
Now, we plug the coordinates into the formula and solve.
(0-(-3))/(6-0)
=3/6
=
So, the slope is
.
Now, we have to find the y-intercept, which is the point where the line on the graph intersects with the y-axis.
We can find the y-intercept (which is represented by b) by plugging the information we already know into the formula.
We can use either pair of coordinates for the formula, so I'll use (6, 0).
y=mx+b
0=
(6)+b
Now, we can solve.
0=3+b
Subtract 3 from both sides.
-3=b
The y-intercept is -3.
Answer:
y=
x-3
Answer:
C. Quadrant III
Step-by-step explanation:
Answer:
A, E, F, D
Step-by-step explanation:
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