0.5 < x < 16.5 given: Two sides of triangle: 8.0 units and 8.5 units
Measure of third side = x
According to the triangle's inequality,
Sum of any two sides > third side. (i)
Difference between the sides < third side. (ii)
If x is the third side, then
x < 8+8.5 [Using (i)]
i.e. x< 16.5
Also, x > 8.5-8 [Using (ii)]
i.e. x> 0.5
Hence, Range of possible sizes for side x would be 0.5 < x < 16.5.
Find the length of the radius.

Find the length of the diameter.
d = 2r = 2 × 5√2 = 10√2
Point B must lie on a line AC, where C is a center of a circle.
Find equation of line AC.
A(–4, 6), C(3, 5)
The distance from B(x, y) to C(3, 5) is 5√2.

Solve system of equations.


Point B could have coordinates

But (–4, 6) are the coordinates of point A.
Therefore, point B has coordinates (10,4).
Answer:
a) k = 5; (-10, -35)
Step-by-step explanation:
Given:
Co-ordinates:
Pre-Image = (-12,3)
After dilation
Image = (-60,15)
The dilation about the origin can be given as :
Pre-Image
where
represents the scalar factor.
We can find value of
for the given co-ordinates by finding the ratio of
or
co-ordinates of the image and pre-image.

For the given co-ordinates.
Pre-Image = (-12,3)
Image = (-60,15)
The value of 
or 
As we get
for both ratios i.e of
and
co-ordinates, so we can say the image has been dilated by a factor of 5 about the origin.
To find the image of (-2,-7), after same dilation, we will multiply the co-ordinates with the scalar factor.
Pre-Image
Image
Pre-Image
Image
(Answer)
The values are just 3 and -1/2 and that is all (:
Answer:
18
Step-by-step explanation: