ΔT = 21º C - 20 ºC => 1 º C
Q = m x C x ΔT
Q = 10 x 0.09 x 1
Q = 0.9 Cal
hope this helps!
Answer: a) Partial pressure of argon is 0.673 atm.
b) Partial pressure of ethane is 0.427 atm.
Explanation:
According to the ideal gas equation:'
P = Pressure of the argon gas = ?
V= Volume of the gas = 1.00 L
T= Temperature of the gas = 25°C = 298 K (0°C = 273 K)
R= Gas constant = 0.0821 atmL/K mol
n= moles of gas = 
Thus the partial pressure of argon is 0.673 atm.
b) According to Dalton's law, the total pressure is the sum of individual pressures.





Thus partial pressure of ethane is 0.427 atm.
Volume would be 6.79792764 cm³. Just divide 131.2 by 19.3
ρ=Mass/Volume
Volume= mass/density
Answer: 15 METERS IN A SECOND
Explanation: 54km = 54000m 54000m / 60 = 900 900/60 = 15