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3 years ago

14

Please help me with this question !!!

1 answer:

Art [367]3 years ago

4 0

Density of the vinegar is higher than the density of the oil.

Explanation:

Density of the vinegar is higher than the density of the oil. The consequence of this is that the oil will be the top layer in the pitcher while the vinegar is at the bottom layer in the pitcher.

When mixing oil and vinegar will not produce a mixture because the oil contains non-polar molecules while vinegar is a solution of acetic acid in water and both of them are polar molecules.

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liquids with different densities

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At 373.15K and 1 atm, the molar volume of liquid water and steamare 1.88 X 10-5 m3 and 3.06 X 10-2m3, respectively. Given that t

professor190 [17]

Answer The value of $\Delta H$ and $\Delta U$ is, 40.79 kJ and 37.7 kJ respectively.

Explanation :

Heat released at constant pressure is known as enthalpy.

The formula used for change in enthalpy of the gas is:

$\Delta Q_p=\Delta H=40.79kJ/mol$

Now we have to calculate the work done.

Formula used :

$w=-P\Delta V\\\\w=-P\times (V_2-V_1)$

where,

w = work done = ?

P = external pressure of the gas = 1 atm

$V_1$ = initial volume = $1.88\times 10^{-5}m^3=1.88\times 10^{-5}\times 10^3L=1.88\times 10^{-2}L$

$V_2$ = final volume = $3.06\times 10^{-2}m^3=3.06\times 10^{-2}\times 10^3L=3.06\times 10^{1}L$

Now put all the given values in the above formula, we get:

$w=-(1atm)\times (3.06\times 10^{1}-1.88\times 10^{-2})L$

$w=-30.5812L.atm=-30.5812\times 101.3J=-3097.87556J=-3.09\times 10^3J=-3.09kJ$

Now we have to calculate the change in internal energy.

$\Delta U=q+w$

$\Delta U=40.79kJ+(3.09kJ)$

$\Delta U=37.7kJ$

Thus, the value of $\Delta H$ and $\Delta U$ is, 40.79 kJ and 37.7 kJ respectively.

4 0

3 years ago

The BEST example of diffraction is the image of

Rashid [163]

Please help me! i only need one more to be the best score

6 0

4 years ago

Read 2 more answers

Calculate the pH of a solution that has [H3O+]=4.3 x 10^-5 M

Neko [114]

Answer:

pH = 4.4

Explanation:

pH = -log[H₃O⁺]

= -log(4.3 × 10⁻⁵)

pH = 4.37 = 4.4

I'm actually learning this in my chemistry class right now lol. Hope this helps though. :)

6 0

3 years ago

Green (Gg) Is crossed with a yellow pea plant (Gg )

Kobotan [32]

GG | Gg
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Gg | gg

5 0

3 years ago

Read 2 more answers

HELP ASAP!!! How many grams of lead are in a 41.2 gram sample of lead (II) oxide? With work please :)

Afina-wow [57]

That would be 58.6 oxide because if the 41.2 plus the oxide would be 48 plus the other particcles inside it so it equaled 58.6 oxide

5 0

3 years ago