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KiRa [710]
3 years ago
7

Why is vsepr theory important?

Chemistry
2 answers:
Serga [27]3 years ago
7 0
It is very important<span> to know the shape of a molecule if one is to understand its reactions. It is also desirable to have a simple method to predict the geometries of compounds. For main group compounds, the </span>VSEPR<span> method is such a predictive tool and unsurpassed as a handy predictive method.</span>
lawyer [7]3 years ago
7 0

Answer:

why molecules have different shapes

Explanation:

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Which state of matter would be described as having highly energized, charged particles that move extremely fast
uranmaximum [27]
There are four states of matter, solid, liquid, gas and plasma. Their formation is as when solid is heated it converts into liquid, liquid on heating converts into gases and gases on heating converts into plasma.

Plasma:
           Plasma is the fourth state of matter. It is the highest energy state of matter.

Composition:
           Plasma is made up of negatively charged and positively charged particles.

Result:
           The answer to your question is Plasma.

8 0
3 years ago
When one material is rubbed against another, electrons jump readily from one to the other. why don’t protons do that?
Pachacha [2.7K]
Protons are held inside nucleous with neutrons with large amount of force. So mere rubbing doesn't help in breaking the nucleous of an atom. But electrons are far from the nucleous and the force of attraction is smaller. So electrons can jump readily while protons can't
5 0
3 years ago
Which of the following best describes the impact of glaciers upon the surface of the earth?
Ahat [919]

Answer:

D. All of the above

Explanation:

Because all of these have something to do with how glaciers are affecting the planet.

6 0
3 years ago
Which of the following terms means that metals can be pulled into thin strands or wires? [like copper]
Dimas [21]

Answer:

D

Explanation:

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5 0
3 years ago
Read 2 more answers
Determine the free energy(ΔG) from the standard cell potential (Ecell0 ) for the reaction:2ClO2-(aq)+Cl2(g)→2ClO2(g)+ 2Cl-(aq)wh
Dima020 [189]

<u>Answer:</u> The \Delta G^o for the given reaction is -7.84\times 10^4J

<u>Explanation:</u>

For the given chemical reaction:

2ClO_2^-(aq.)+Cl_2(g)\rightarrow 2ClO_2(g)+2Cl^-(aq.)

Half reactions for the given cell follows:

<u>Oxidation half reaction:</u> ClO_2^-\rightarrow ClO_2+e^-;E^o_{ClO_2^-/ClO_2}=0.954V  ( × 2)

<u>Reduction half reaction:</u> Cl_2+2e^-\rightarrow 2Cl(g);E^o_{Cl_2/2Cl^-}=1.36V

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{cathode}-E^o_{anode}

Putting values in above equation, we get:

E^o_{cell}=1.36-(0.954)=0.406V

To calculate standard Gibbs free energy, we use the equation:

\Delta G^o=-nFE^o_{cell}

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

E^o_{cell} = standard cell potential = 0.406 V

Putting values in above equation, we get:

\Delta G^o=-2\times 96500\times 0.406=-78358J=-7.84\times 10^4J

Hence, the \Delta G^o for the given reaction is -7.84\times 10^4J

4 0
3 years ago
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