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KiRa [710]
3 years ago
7

Why is vsepr theory important?

Chemistry
2 answers:
Serga [27]3 years ago
7 0
It is very important<span> to know the shape of a molecule if one is to understand its reactions. It is also desirable to have a simple method to predict the geometries of compounds. For main group compounds, the </span>VSEPR<span> method is such a predictive tool and unsurpassed as a handy predictive method.</span>
lawyer [7]3 years ago
7 0

Answer:

why molecules have different shapes

Explanation:

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Which of these atoms are electrically neutral?
Xelga [282]

Atoms are electrically neutral because they contain equal quantities of positively charged protons and negatively charged electrons. Electrons and protons have equal but opposite charges, so the result is no net charge. Ions are atoms that have gained or lost electrons.

4 0
3 years ago
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Write the reaction when solid aluminum sulfate is put into water:
valentina_108 [34]
It's quite strong and has a weak base . it would probably dissolve and the ph would drop
5 0
3 years ago
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What is the heat capacity of crystalline calcium carbide at 49.0°C?
Olenka [21]

Explanation:

Formula to calculate heat capacity is as follows.

               C_{p} = a + bT + cT^{-2}

where, a, b and c are constants.

Their values at 49.0^{o}C are as follows.

     a = 68.62 \times 10^{-3}        

     b = 1.19 \times 10^{-5}

     c = -8.66 \times 10^{10} \times 10^{-8}

Hence, putting the given values into the above formula as follows.

               C_{p} = a + bT + cT^{-2}

    = 68.62 \times 10^{-3} + 1.19 \times 10^{-5} \times 49.0 + -8.66 \times 10^{10} \times 10^{-8} \times (49.0)^{-2} kJ/mol K    

                             = 14.43 kJ/mol K

Thus, we can conclude that the heat capacity of crystalline calcium carbide at 49.0^{o}C is 14.43 kJ/mol K.

4 0
3 years ago
Two balls are at the same time height and released at the same time. One ball is dropped and hits the ground 5 s later. The othe
marusya05 [52]

Answer:the other ball hits the ground

15 seconds later

Explanation:

7 0
3 years ago
What volume of a concentrated HCl solution, which is 36.0% HCl by mass and has a density of 1.179 g/mL, should be used to make 5
charle [14.2K]

Answer:

The volume we need is 8.89 mL

Explanation:

We analyse data:

36 % by mass → 36 g of HCl in 100 g of solution

Solution's density = 1.179 g/mL

5.20L → Volume of diluted density

pH = 1.70 → [H⁺] = 10⁻¹'⁷⁰ = 0.0199 M

 HCl    →       H⁺     +    Cl⁻

                 0.0199

pH can gives the information of protons concentrations, so as ratio is 1:1, 0.0199 M is also the molar concentration of HCl

Let's verify the molar concentration of the concentrated solution:

We convert the mass to moles: 36 g / 36.45 g/mol = 0.987 moles

As the solution mass is 100 g, we apply density to find out the volume:

Density = Mass / volume → Volume = Mass / Density

Volume = 100 g / 1.179 g/mL → 84.8 mL

Let's convert the volume from mL to L in order to define molarity

84.8 mL . 1L/ 1000mL = 0.0848 L

Molarity → 0.987 mol / 0.0848L = 11.6M

Let's apply the dilution formula:

M concentrated . V concentrated = M diluted . V diluted

11.6 M . V concentrated = 0.0199M . 5.20L

V concentrated = (0.0199M . 5.20L) / 11.6M → 8.89×10⁻³L

We can say, that the volume we need is 8.89 mL

8 0
3 years ago
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