A) 140 degrees
First of all, we need to find the angular velocity of the Ferris wheel. We know that its period is
T = 32 s
So the angular velocity is
Assuming the wheel is moving at constant angular velocity, we can now calculate the angular displacement with respect to the initial position:
and substituting t = 75 seconds, we find
In degrees, it is
So, the new position is 140 degrees from the initial position at the top.
B) 2.7 m/s
The tangential speed, v, of a point at the egde of the wheel is given by
where we have
r = d/2 = (27 m)/2=13.5 m is the radius of the wheel
Substituting into the equation, we find
We can answer the problem by Snell's Law:
Snell's law<span> (also known as </span>Snell<span>–Descartes </span>law<span> and the </span>law<span> of refraction) is a formula used to describe the relationship between the angles of incidence and refraction, when referring to light or other waves passing through a boundary between two different isotropic media, such as water, glass, or air.</span>
Answer:
False
Explanation:
The Sun rotates in this same, right-hand-rule direction. All planetary orbits lie in nearly the same plane. All planetary orbits are nearly circular (eccentricity near zero).
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Carbon-14 has a relatively small half life of 5,730 years
Given data:
Wave length (λ) = 2.30 m,
Frequency (f) = 370 Hz (waves/sec),
Determine the speed of the wave = ?
Speed of the wave is defined as "the distance a wave travels in a given time". And it is a product of <em>wavelength (λ) </em>and <em>frequency(f). </em>
An Important point to be remember here is <em>"when increasing the wave length of the wave does not increase the speed of the wave"</em> because the wave speed also depends on frequency (f), So, if the wave length increases wave speed decreases. As a result the product of wave length and frequency are same.
Mathematically,
Wave speed = wave length × frequency
= 2.30 m × 370 waves/sec.
= 851 m/s.
<em>Speed of the wave is 851 m/s</em>
