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lorasvet [3.4K]
3 years ago
12

Carbon monoxide poisoning is sometimes mistakenly identified as what?

Chemistry
2 answers:
liq [111]3 years ago
4 0
Seasickness. The symptoms of carbon monoxide poisoning mimic the symptoms of seasickness.
xeze [42]3 years ago
4 0
Carbon monoxide poisoning is sometimes mistaken to be s<span>easickness. Hope this helps!</span>
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What is the maximum number of covalent
Lera25 [3.4K]

Answer:

D. 4

Explanation:

Answer and Explanation: Carbon can form a maximum of four covalent bonds. Carbon can share up to four pairs of electrons, therefore, the carbon atom fills its outer energy level and achieves chemical stability.

4 0
2 years ago
How many molecules of carbon dioxide are in 9.080 x 10 ^-1 mol?
kakasveta [241]

Answer:

5.46 8 x 10²³ molecules.

Explanation:

  • <em>Knowing that every one mole of a substance contains Avogadro's no. of molecules (NA = 6.022 x 10²³).</em>

<em><u>Using cross multiplication:</u></em>

1.0 mole → 6.022 x 10²³ molecules.

9.08 x 10⁻¹ mole → ??? molecules.

∴ The no. of molecules of CO₂ are in 9.08 x 10⁻¹ mol = (6.022 x 10²³ molecules) ( 9.08 x 10⁻¹ mole) / (1.0 mol) = 5.46 8 x 10²³ molecules.

6 0
3 years ago
Which statement below references interactions between the geosphere, the hydrosphere and the biosphere?
erastovalidia [21]
Ekekoskekeoejekskdodjdod
7 0
3 years ago
Read 2 more answers
The boiling points of different substances are given in the table below.
Oksi-84 [34.3K]

Answer:

Water

Explanation :-

Higher the intermolecular forces between the liquid particles, higher its boiling point.

8 0
3 years ago
What molarity of nitric acid (HNO3) was used if 2.00 L must be used to prepare 4.5 L of a 0.25 M HNO3 solution?
Ymorist [56]

The   molarity  of (HNO₃) that was used  if 2.00 L must  be used   to prepare 4.5 L  of a 0.25M HNO₃ solution is   0.563 M


 <u><em>calculation</em></u>

  This is calculated  usind  M₁V₁=M₂V₂  formula

where,

         M₁(  molarity ₁) = ?

         V₁( volume ₁) = 2.00 L

        M₁ (molarity ₂) = 0.25M

         V₂( volume₂) = 4.5 L

make M₁ the subject  of the formula by  diving both side of the formula  by V₁

   M₁  is therefore = M₂V₂/V₁

M₁ =[ (0.25 M  x 4.5 L) / 2.00 L ]  =0.563 M

5 0
3 years ago
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