The Equator is where the doldrums are found.
Answer:
5.0 moles.
Explanation:
- The balanced equation of the reaction between hydrogen and oxgen to produce water is:
<em>H₂ + 1/2O₂ → H₂O.</em>
- It is clear that 1.0 mole of H₂ reacts with 0.5 mole of O₂ to produce 1.0 mole of H₂O.
∴ 2.5 mole of O₂ will react with 5.0 moles of H₂.
- The limiting reactant is O₂ and H₂ is found in excess (1.0 mole more).
From the stichiometry: 2.5 mole of O₂ will react with 5.0 moles of H₂ to produce 5.0 moles of H₂O.
<em>∴ 5.0 moles of water are produced when 6.0 moles of hydrogen gas react with 2.5 moles of oxygen gas</em>
Answer:
the answer is 3.33⋅1023 molecules of Cl2. Note that 6.022⋅1023 is also known as Avogadro's number, and it can be referred to as the number of molecules in one mole of that substance. Also, I calculated 70.9 because 35.45 g/mol (the mass of one Chlorine atom) times 2 is 70.9 g/mol (Cl2 has two Chlorine atoms).
Explanation:
Answer:
The correct answer is Option C (E1) and Option B (carbocation).
Explanation:
- Intramolecular immunity idols are considered as that of the formation mechanism with E1 responses or reactivity.
- Reactants with E1 were indeed obligations of both parties, meaning that an E1 reaction was conducted thru all the two stages known as ionization but rather deprotonation. Involves the absence of either an aromatic ring, a carbocation has been generated throughout the ionization solution.
Some other possibilities offered aren't relevant to the procedure outlined. So the above alternative is accurate.
Answer:
solid density = 3.85 g/mL
Explanation:
First we calculate the mass of the benzene:
benzene mass = 63.29 - 25 = 38.29 g
We know that density = mass / volume
So the volume of benzene will be:
volume = mass / density
volume = 38.29 / 0.880 = 43.51 cm³ = 43.51 mL of benzene (1 cm³ = 1 mL)
Now the volume of the sample will be:
sample volume = 50 - 43.51 = 6.49 mL
Now we can calculate the density of the solid:
density = mass / volume
solid density = 25 / 6.49 = 3.85 g/mL