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s344n2d4d5 [400]
4 years ago
5

You have at your disposal 3 1-pound bags of various pure salts that dissolve readily in water. You can add one of the bags to a

55 gallon barrel of water. Which bag should you use to lower the freezing point by the greatest amount? (1 lb. = 0.454 kg)
Chemistry
1 answer:
Sedaia [141]4 years ago
6 0

Answer:

This question appears incomplete

Explanation:

However, it should be noted that addition of soluble salts generally lowers the freezing point of water hence after the addition, water will no longer freeze at 0°C but lower.

Soluble salts tend to form more ions in water, it is these ions that are responsible for interfering with the hydrogen bonds hence lowering the freezing. Thus, (since each bag are of the same weight) <u>the bag that contains the salt that ionizes more in water will lower the freezing point by the greatest amount</u>.

NOTE: Different weight of the salts could lead to more ions been formed in the water by some salts as against the other.

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Acid+base-&gt;salt+water<br>What type of reaction is this?​
Lelechka [254]

Answer:

The reaction of an acid with a base is called a neutralization reaction. The products of this reaction are a salt and water.

5 0
3 years ago
Read 2 more answers
Determine the molar mass of a gas that moves 1.25 times as fast as CO2.
Lerok [7]

The molar mass of a gas that moves 1.25 times as fast as CO2 is 28.16 g.

<h3>Molar mass of the gas</h3>

The molar mass of the gas is determined by applying Graham's law of diffusion.

R₁√M₁ = R₂√M₂

R₁/R₂ = √M₂/√M₁

R₁/R₂ = √(M₂/M₁)

where;

  • R₁ is rate of the CO2 gas
  • M₁ is  molar mass of CO2 gas
  • R₂ is rate of the second gas
  • M₂ is the molar mass of the second gas

R₁/1.25R₁ = √(M₂/44)

1/1.25 =  √(M₂/44)

0.8 = √(M₂/44)

0.8² = M₂/44

M₂ = 0.8² x 44

M₂ = 28.16 g

Thus, the molar mass of a gas that moves 1.25 times as fast as CO2 is 28.16 g.

Learn more about molar mass here: brainly.com/question/21334167

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3 0
2 years ago
How many moles of h2o are equivalent to 97.3 grams of h20
g100num [7]

Answer : 5.405 moles of H_2O are equivalent to 97.3 grams of H_2O

Solution : Given,

Mass of H_2O = 97.3 g

Molar mass of H_2O = 18 g/mole

Formula used :

\text{ Number of moles}=\frac{\text{ Given mass}}{\text{ Molar mass}}

or,

\text{ Number of moles of }H_2O=\frac{\text{ Given mass of }H_2O}{\text{ Molar mass of }H_2O}

Now put all the given values in this formula, we get the moles of H_2O

\text{ Number of moles of }H_2O=\frac{97.3g}{18g/mole}=5.405moles

Therefore, 5.405 moles of H_2O are equivalent to 97.3 grams of H_2O

6 0
3 years ago
You are presented with a mystery as part of your practical experiment. You have a solution of Pb(NO3)2
shusha [124]
Ho123 right I’m sorry of I’m wrong
7 0
3 years ago
48 points
ahrayia [7]

Answer:

1. Matter

2. Mass

3. Space/Volume

4. Substances

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9. Atomic

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11.

12. Atomic

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6 0
3 years ago
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