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A mixture of carbon dioxide and helium gases is maintained in a 7.91 L flask at a pressure of 1.42 atm and a temperature of 33 °

Crank

Answer:

The gas mixture contains 1.038 grams of helium

Explanation:

Step 1: Data given

Volume of the flask = 7.91 L

Total Pressure = 1.42 atm

Temperature = 33 °C

Mass of CO2 = 8.25 grams

Molar mass of CO2 = 44.01 g/mol

Molar mass of He = 4 g/mol

Step 2: Calculate total number moles of gas

p*V = n*R*T

⇒ p = the pressure = 1.42 atm

⇒ V = the volume = 7.91 L

⇒ n= the number of moles = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L* atm/K*mol

⇒ T = the temperature = 33 °C = 306 Kelvin

n = (p*V)/(R*T)

n = (1.42*7.91)/(0.08206 * 306)

n = 0.447 moles

Step 3: Calculate moles of CO2

Moles CO2 = mass CO2 / Molar mass CO2

Moles CO2 = 8.25 grams / 44.01 g/mol

Moles CO2 = 0.1875 moles

Step 4: Calculate moles of Helium

Moles Helium = total moles of gas - moles of CO2

Moles Helium = 0.447 - 0.1875 = 0.2595 moles of helium

Step 5: Calculate mass of helium

Mass of helium = moles of helium * molar mass of helium

Mass of helium = 0.2595 moles * 4 g/mol

Mass of helium = 1.038 grams

The gas mixture contains 1.038 grams of helium

8 0

3 years ago

2C_H. + 702 — 400, + 6H2O

astra-53 [7]

Balanced Eqn

2

C

2

H

6

+

7

O

2

=

4

C

O

2

+

6

H

2

O

By the Balanced eqn

60g ethane requires 7x32= 224g oxygen

here ethane is in excess.oxygen will be fully consumed

hence

300g oxygen will consume

60

⋅

300

224

=

80.36

g

ethane

leaving (270-80.36)= 189.64 g ethane.

By the Balanced eqn

60g ethane produces 4x44 g CO2

hence amount of CO2 produced =

4

⋅

44

⋅

80.36

60

=

235.72

g

and its no. of moles will be

235.72

44

=5.36 where 44 is the molar mass of Carbon dioxide

hope this helps

6 0

3 years ago

What ion (cation or anion and charge) do the halogen group (17) form to fulfill the octet

Dafna11 [192]

Answer:

option B= anion (-1)

Explanation:

The halogens are present in the P- block of periodic table. There are thirty five elements present in p-block. The halogens are present in group seventeen. Their are seven electrons are present in valance sheet. All halogens require one electron to complete the octet and form anion carry -1 charge.

Halogens include following elements:

Fluorine, chlorine, bromine, iodine and astatine.

The halogens mostly form single bond with the other elements by gaining one electron and -1 charge. These are most reactive non-metals.

Properties of some halogen elements:

Fluorine:

1. It is yellow in color.

2. It is flammable gas.

3. It is highly corrosive.

4. Fluorine has pungent smell.

5. It's reactions with all other elements are vigorous except neon, oxygen, krypton and helium.

Chlorine:

1. It is greenish-yellow irritating gas.

2. Its melting point is 172.2 K.

3. Its boiling point is 238.6 K.

4. It is disinfectant and can kill the bacteria.

5. It is also used in manufacturing of paper, paints and textile industries.

Iodine:

1. It is present in solid form.

2. It is crystalline in nature.

3. It is very corrosive and has pungent odor.

4. It can not react with oxygen and nitrogen.

6 0

3 years ago

Calculate the mass in grams of each sample. 4.88x10^20 H2O2 molecules

AleksAgata [21]

4.88x10^20 H2O2 molecules

5 0

3 years ago

Hey! I need a simple connotation of how glowsticks glow. Please and thank you.

LenaWriter [7]

Answer:

simple

Explanation:

The glow stick's outer plastic tube holds a solution of an oxalate ester and an electron-rich dye along with a glass vial filled with a hydrogen peroxide solution. ... Glow sticks light up when oxalate esters react with hydrogen peroxide to form a high-energy intermediate

5 0

2 years ago