Answer:
c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Thus, the rate is given as:
![rate=-\frac{1}{2} \frac{\Delta [HBr]}{\Delta t}=\frac{\Delta [Br_2]}{\Delta t} =\frac{\Delta [H_2]}{\Delta t}](https://tex.z-dn.net/?f=rate%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cfrac%7B%5CDelta%20%5BHBr%5D%7D%7B%5CDelta%20t%7D%3D%5Cfrac%7B%5CDelta%20%5BBr_2%5D%7D%7B%5CDelta%20t%7D%20%3D%5Cfrac%7B%5CDelta%20%5BH_2%5D%7D%7B%5CDelta%20t%7D)
It is necessary to remember that each concentration to time interval is divided into the stoichiometric coefficient, that is why HBr has a 1/2. Moreover, the concentration HBr is negative since it is a reactant and it has a negative rate due to its consumption.
Therefore, the answer is:
c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt
Best regards.
<span> A compound <span>lens microscope. </span></span>
I am assuming that the problem ask for the pressure in
the system. To be able to calculate this, we first assume that the system acts
like an ideal gas, then we can use the ideal gas equation to find for pressure
P.
P V = n R T
where,
P = Pressure (unknown)
V = 0.17 m^3
n = moles of lng / methane
R = gas constant = 8.314 Pa m^3 / mol K
T = 200 K
We find for the moles of lng. Molar mass of methane = 16
kg / kmol
n = 55 kg / 16 kg / kmol
n = 3.44 kmol CH4 = 3440 mol
Substituting all the values to the ideal gas equation:
P = 3440 mol * (8.314 Pa m^3 / mol K) * 200 K / 0.17 m^3
P = 33,647,247 Pa
<span>P = 33.6 MPa</span>
The best and most correct answer among the choices provided by your question is the third choice or letter D.
<span>Solids, liquids, gases and plasma are all made of atoms.</span>
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