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anyanavicka [17]
3 years ago
7

What are the measures of the angles located at positions a, b, c, d, e, & f?

Mathematics
1 answer:
harkovskaia [24]3 years ago
4 0

92 make since i think lol

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tom's baseball team wins 5 out every 12 games they play. If the team played 36 games, how many games did Tom's team win
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Help fast. do first question only and please show work thx.
amm1812
Y = -0.01x^2 + 0.5x + 3

when the height y = 8 
-0.01x^2 + 0.5x + 3 = 8
-0.01x^2 + 0.5x - 5 = 0

x =  13.82 and x = 36.18 so the ball is at least 8 ft high   from 13.82 and 36.18 feet inclusive.- from the player.

If the player is 30 ft from the net then the ball is likely to go over the net.
7 0
3 years ago
FIRST TO ANSWER GETS BRAINLIEST!
scZoUnD [109]

Answer:

\huge \boxed{ \red{ \boxed{c)78 \: units ^{2} }}}

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • circle
  • PEMDAS
<h3>tips and formulas:</h3>
  • \rm \:A_{shaded}=  \dfrac{\theta}{360}  \times \pi {r}^{2}
<h3>let's solve:</h3>
  1. \sf sustitute \: the \: value \: of \:  \theta \: and \: r :  \\ A_{shaded} =  \frac{140}{360}  \times \pi \times  {8}^{2}
  2. \sf simpify \: squre :  \\ A_{shaded} =  \frac{140}{360}  \times \pi \times  64
  3. \sf simpify \: fraction:  \\ A_{shaded} =  \frac{7}{18}  \times \pi \times  64
  4. \sf  reduce \: 64:  \\ A_{shaded} =  \frac{7}{ \cancel{ \: 18} \:  ^{9} }  \times \pi \times  \cancel{ 64}  \: ^{32}  \\ A_{shaded} =  \frac{7}{9} \times \pi \times 32\\ A_{shaded} =  \frac{224\pi}{9}

\large A_{shaded}\approx 78 \: square  \: units

8 0
3 years ago
Read 2 more answers
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