Given: Each block has masses m1 = m2 = m3 = m and the coefficient of kinetic friction is µ. The magnitude of F equals twice the
total frictional force. Apply a horizontal force F in pushing an array of three identical blocks in the horizontal plane (see sketch). m1 m2 m3 F µ Find the force F23 with which the second block is pushing the third block.
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Answer:
Power=V*I which corresponds to the second option shown: "voltage times amperage"
Explanation:
The electric power is the work done to move a charge Q across a given difference of potential V per unit of time.
Since such electrical work is the product of the potential difference V times the charge that moves through that potential, and this work is to be calculated by the unit of time, we need to divide the product by time (t) which leads to the following final simple equation