Given: Each block has masses m1 = m2 = m3 = m and the coefficient of kinetic friction is µ. The magnitude of F equals twice the
total frictional force. Apply a horizontal force F in pushing an array of three identical blocks in the horizontal plane (see sketch). m1 m2 m3 F µ Find the force F23 with which the second block is pushing the third block.
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Answer:3.56 nanosecond
In this case, you are asked the time and given the light distance(3.5ft)
To answer this question you would need to know the velocity of light. Speed of light is <span>299792458m/s. Then the calculation would be:
time= distance/speed
time= 3.5 ft / (</span>299792458m/s) x 0.3048 meter/ 1 ft= 3.56
second or 3.56 nanosecond
In this case, you are asked the time and given the light distance(3.5ft)
To answer this question you would need to know the velocity of light. Speed of light is <span>299792458m/s. Then the calculation would be:
time= distance/speed
time= 3.5 ft / (</span>299792458m/s) x 0.3048 meter/ 1 ft= 3.56