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GREYUIT [131]
3 years ago
15

5 What is the kinetic energy of a 28 kg car moving at a velocity of 7 m/s O 1963 98 686 J O 350 nocter diagram, at which point w

ould the kinetic energy of the​
Physics
1 answer:
Shtirlitz [24]3 years ago
4 0

Answer:

98 joules

Explanation:

1/2 of 28 = 14

14 multiply by 7= 98 joules

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You are on a school bus driving north at 20 m/s. You walk toward the back of the bus with a velocity of 6 m/s. What is your velo
Ganezh [65]
I answered the question but it got deleted?? why?
3 0
3 years ago
Identify the frequency used by these broadcast media.<br><br> FM<br> AM<br> Television
Oliga [24]

Answer:

AM radio = 540 - 1650 KHz

FM radio = 88 to 108 MHz

Television = 54 to 216 MHz

7 0
4 years ago
Read 2 more answers
a wooden block has a mass of 1.2 kg, a specific heat of 710, and is at a temperature of 25*C. what is the block's final temperat
mash [69]

The final temperature of the block is 27.5^{\circ} C

Explanation:

The amount of thermal energy Q supplied to a substance is related to the increase in temperature of the substance, \Delta T, according to the equation

Q=mC_s \Delta T

where:

m is the mass of the substance

C_s is the specific heat capacity of the substance

In this problem, we have:

m = 1.2 kg is the mass of the block

Q = 2,130 J is the amount of energy supplied to the block

C_s = 710 J/kg^{\circ}C is the specific heat capacity of the block

Solving for \Delta T, we find the increase in temperature:

\Delta T = \frac{Q}{m C_s}=\frac{2130}{(1.2)(710)}=2.5^{\circ}C

And since the initial temperature was

T_i = 25^{\circ}C

The final temperature will be

T_f = T_i + \Delta T = 25+2.5=27.5^{\circ} C

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

8 0
3 years ago
Calculate the density of a substance that has mass 10g and volume 2mL
noname [10]

You're supposed to divide the mass by the volume, which is going to equal to 5

4 0
3 years ago
The function x = (7.8 m) cos[(5πrad/s)t + π/3 rad] gives the simple harmonic motion of a body. At t = 4.4 s, what are the (a) di
VMariaS [17]

Answer:

a.3.84m

b.-106.67m/s

c.947.3m/s^2

d.70.17 rad

e.2.5Hz

d.0.4secs

Explanation:

Given x=(7.8)cos[5πrad/s)t+π/3)]

a.Displacement at t=4.4

7.8cos(5π*4.4+π\3)=3.84m

b.velocity

V= dx/dr=-5π(7.8)sin(5πrad/s)t+π\3

at t=4.4

-5π(7.8)sin(5π*4.4+π\3)=-106.67m/s

c.acceleration

a=d^2x/dr^2

-(5π)^2(7.8) cos (5π*t+π\3)

at t=4.4

-(5π)^2(7.8)cos(5π*4.4+π\3)=-947.3m/s^2

d. Phase =(5πrad/s)t+π\3

At t=4.4

5π×4.4+π\3=70.17 rad

e.frequency

Given x= 7.8cos(5πt+π\3

Compare with x=Acos(2πft)

2πft=5πt

F=2.5Hz

f.T=1\f

T=1/2.5=0.4sec

6 0
3 years ago
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