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3 years ago

What does it mean? I need help with this

Mathematics

1 answer:

kykrilka [37]3 years ago

8 0

In order to do mean you have to add all of the numbers in the list together. then divide them by the total amount of numbers (ex. 7,9,3,2,5. you would add all of these up 7+9+3+2+5=26 then you would divide that by 5 because there are five numbers in the list.

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If one point on a horizontal line has the coordinates (10, -3), which of the points below are also on the line? Select all that

frozen [14]

The correct answers are:
______________________________________________________
[B]: " (3, -3) " ; AND:
______________________________________________________
[C]: " (-2, -3) " .
______________________________________________________
<u>
Note</u>: Any point with the "y-coordinate" of "-3" would also be on the line.

As such, the correct answers, are:
______________________________________________________
[B]: " (3, -3) " ; AND:
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[C]: " (-2, -3) " .
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6 0

3 years ago

3/4 of a class are girls. 1/3 of the girls wear bows in their hair. What fraction of the class are girls with bows in her hair

Svetradugi [14.3K]

Answer:

Step-by-step explanation:

1/3 * 3/4 = 1/4

7 0

3 years ago

64 miles per hour/ in feet per second

Dafna11 [192]

The answer would be 93.8667 feet per second.

64 miles to feet is 337,920

1 hour = 3600 seconds.

337,920 ÷ 3600 = 93.8667

8 0

3 years ago

Tacoma's population in 2000 was about 200 thousand, and had been growing by about 9% each year. a. Write a recursive formula for

KIM [24]

Answer:

a) The recurrence formula is $P_n = \frac{109}{100}P_{n-1}$ .

b) The general formula for the population of Tacoma is

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) In 2016 the approximate population of Tacoma will be 794062 people.

d) The population of Tacoma should exceed the 400000 people by the year 2009.

Step-by-step explanation:

a) We have the population in the year 2000, which is 200 000 people. Let us write $P_0 = 200 000$ . For the population in 2001 we will use $P_1$ , for the population in 2002 we will use $P_2$ , and so on.

In the following year, 2001, the population grow 9% with respect to the previous year. This means that $P_0$ is equal to $P_1$ plus 9% of the population of 2000. Notice that this can be written as

$P_1 = P_0 + (9/100)*P_0 = \left(1-\frac{9}{100}\right)P_0 = \frac{109}{100}P_0$ .

In 2002, we will have the population of 2001, $P_1$ , plus the 9% of $P_1$ . This is

$P_2 = P_1 + (9/100)*P_1 = \left(1-\frac{9}{100}\right)P_1 = \frac{109}{100}P_1$ .

So, it is not difficult to notice that the general recurrence is

$P_n = \frac{109}{100}P_{n-1}$ .

b) In the previous formula we only need to substitute the expression for $P_{n-1}$ :

$P_{n-1} = \frac{109}{100}P_{n-2}$ .

Then,

$P_n = \left(\frac{109}{100}\right)^2P_{n-2}$ .

Repeating the procedure for $P_{n-3}$ we get

$P_n = \left(\frac{109}{100}\right)^3P_{n-3}$ .

But we can do the same operation n times, so

$P_n = \left(\frac{109}{100}\right)^nP_{0}$ .

c) Recall the notation we have used:

$P_{0}$ for 2000, $P_{1}$ for 2001, $P_{2}$ for 2002, and so on. Then, 2016 is $P_{16}$ . So, in order to obtain the approximate population of Tacoma in 2016 is